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Vinvika [58]
3 years ago
11

Help please!!!!!!!!!!!!

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

\frac{\pi }{3},\:\frac{2\pi }{3}

Step-by-step explanation:

Let a=THETA (angle)

1+\sin \left(a\right)-1=\frac{\sqrt{3}+2}{2}-1\\\sin \left(a\right)=\frac{\sqrt{3}+2}{2}-1\\a=\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n,\:a=\pi -\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n\\a=\frac{\pi }{3},\:a=\frac{2\pi }{3}

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