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wolverine [178]
3 years ago
14

Six less than five times a number is three more than twice the number.

Mathematics
2 answers:
nignag [31]3 years ago
8 0

Answer:

5x - 6 -3= 2x

Step-by-step explanation:

Oksanka [162]3 years ago
7 0

Answer:

5x-6=2x+3

Step-by-step explanation:

six less than - so you subtract six from five time a number

five times a number - number is unknown so you use the variable "x"

is - equals

three more than - so you add three to two times the number

two times the number - the same number so it's represented with the same variable

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185 shrubs

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Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

x:\text{Time} \\ \\ y:\text{Number of teams registered}

We also know that each week 6 teams register to participate, so:

\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

y=6x

In conclusion, <em>the linear model (first graph below) is the one that bests represents  the relationship between time and the number of teams registered.</em>

7 0
3 years ago
Help with both questions offering 10 points
Alexandra [31]

Answer:

\:\mathrm{First\: problem:\:}-2,\\\:\mathrm{Second\: problem:\: }-3

Step-by-step explanation:

The slope of a line passing through points (x_1, y_1) and (x_2, y_2) is:

m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}

Plugging in any two points in the table we have:

<u>First problem:</u>

<u />m=\frac{1-5}{2-0}=\frac{-4}{2}=\fbox{$-2$}<u />

<u>Second problem:</u>

<u />m=\frac{-1-5}{2-0}=\frac{-6}{2}=\fbox{$-3$}<u />

8 0
3 years ago
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