Start by graphing each line.
• Because the first inequality is smaller than, it will have a dotted (- - -) line.
• Because the second inequality is smaller than or equal to, it will have a solid line (---).
Then, plug in points to see where your shading will go. If the statement is true (x = x), you will shade that area along the line.
0 is less than 2.
Do the same step for the other equation. Your solution to the problem is any point that lies between the shading from both inequalities (where the blue and red meet).
Answer: The average rate of change is 6.First, plug in each value of <em>t</em> into the function, v(t) to find there coordinate pairs.
v(2) = (2)^2 - (2) + 10
v(2) = 4 + 8
v(2) = 12
v(5) = (5)^2 - (5) + 10
v(5) = 25 + 5
v(5) = 30
You can write these values as coordinate pairs, like so: (2, 12) and (5, 30).
The formula for the average rate of change is
. When you plug in the values from this particular case, the average rate of change formula becomes
, or
.
Looking at the equation, you can solve for the average rate of change between t = 2 and t = 5, which equals
6.
Answer:
6
Step-by-step explanation:
You are looking for the cross section of ask three circles. This is true for the smallest part, with the number 6 in it.
Answer:
Hulian's age is 7.
Thomas's age is 22.
Step-by-step explanation:
Let Hulian = h
Let Thomas = t
Set the system of equation:
h = t - 15
h + t = 29
Plug in t - 15 for h in the second equation:
(t - 15) + t = 29
Simplify. Combine like terms:
2t - 15 = 29
Isolate the variable, t. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, add 15 to both sides:
2t - 15 (+15) = 29 (+15)
2t = 44
Divide 2 from both sides:
(2t)/2 = (44)2
t = 44/2
t = 22
Plug in 22 for t in one of the equations:
h = t - 15
h = 22 - 15
h = 7
Hulian's age is 7.
Thomas's age is 22.
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