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3 years ago

9

Dierections in picture please help 14x2 - 42x

1 answer:

Archy [21]3 years ago

3 0

Answer:

-14 is the answer. 14x2=28-42= -14

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Evaluate the expression when z= -12<br> 1/2z^2

icang [17]

Answer:

Exact Form: z = 0, -2/25

Decimal Form: 0, -0.08

Step-by-step explanation:

I used cymath.com. I highly recommend it. It shows you the steps to the problem you want to solve!

I hope this helps! :)

The last step is to solve for z

8 0

3 years ago

3x-4y=1 and x=2y+1 using substitution

Aleksandr [31]

Answer:

x =-1

y =-1

Step-by-step explanation:

to solve this system of equation, using substiution method

3x-4y=1 ........................ equation 1

x=2y+1 ............................ equation 2

subbstitute for x into equation 1

3x-4y=1 ........................ equation 1

3(2y + 1) - 4y = 1

6y + 3 -4y = 1

2y + 3 = 1

collect the like terms

2y = 1- 3

2y= -2

divide both sides by the coefficient of y which is y

2y/2 = -2/2

y = -1

put the value of y =-1 into equation 2

x=2y+1 ............................ equation 2

x = 2(-1) + 1

x = -2 + 1

x = -1

therefore x =-1 y = -1

3 0

4 years ago

There are 18 boys on a football team. Of the team, 1/3 of the boys are 12 years-old. Of the 12 year-olds, 1/3 have never played

kakasveta [241]

Answer:

1/9

Step-by-step explanation:

1/3 *1/3 = 1/9

8 0

3 years ago

1. Construct a table of values of the following functions using the interval of 5

Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

$g(x) = \frac{x^3 + 3x - 5}{x^2}$

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When $x = -5$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}$

$g(-5) = \frac{-125 -15 - 5}{25}$

$g(-5) = \frac{-145}{25}$

$g(-5) = -5.8$

When $x = -4$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}$

$g(-4) = \frac{-64 -12 - 5}{16}$

$g(-4) = \frac{-81}{16}$

$g(-4) = -5.0625$

When $x = -3$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}$

$g(-3) = \frac{-27 -9 - 5}{9}$

$g(-3) = \frac{-41}{9}$

$g(-3) = -4.56$

When $x = -2$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}$

$g(-2) = \frac{-8 -6 - 5}{4}$

$g(-2) = \frac{-19}{4}$

$g(-2) = -4.75$

When $x = -1$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}$

$g(-1) = \frac{-1 + 3 - 5}{1}$

$g(-1) = \frac{-3}{1}$

$g(-1) = -3$

When $x = 0$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(0) = \frac{0^3 + 3(0) - 5}{0^2}$

$g(0) = \frac{0 + 0 - 5}{0}$

$g(0) = \frac{- 5}{0}$

<em>g(0) = undefined</em>

When $x = 1$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(1) = \frac{1^3 + 3(1) - 5}{1^2}$

$g(1) = \frac{1 + 3 - 5}{1}$

$g(1) = \frac{-1}{1}$

$g(1) = 1$

When $x = 2$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(2) = \frac{2^3 + 3(2) - 5}{2^2}$

$g(2) = \frac{8 + 6 - 5}{4}$

$g(2) = \frac{9}{4}$

$g(2) = 2.25$

When $x = 3$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(3) = \frac{3^3 + 3(3) - 5}{3^2}$

$g(3) = \frac{27 + 9 - 5}{9}$

$g(3) = \frac{31}{9}$

$g(3) = 3.44$

When $x = 4$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(4) = \frac{4^3 + 3(4) - 5}{4^2}$

$g(4) = \frac{64 + 12 - 5}{16}$

$g(4) = \frac{71}{16}$

$g(4) = 4.4375$

When $x = 5$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(5) = \frac{5^3 + 3(5) - 5}{5^2}$

$g(5) = \frac{125 + 15 - 5}{25}$

$g(5) = \frac{135}{25}$

$g(5) = 5.4$

<em>Hence, the complete table is:</em>

x ---- g(x)

-5 --- -5.8

-4 --- -5.0625

-3 --- -4.56

-2 --- -4.75

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0

3 years ago

What five-digit positive integer with an 8 in the ten-thousands place is the cube of an integer?

Sloan [31]

Answer:

44

Step-by-step explanation:

44^3 = 85,184

five digit positive

eight in the ten thousand place

4 0

3 years ago