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BigorU [14]
3 years ago
9

Dierections in picture please help 14x2 - 42x

Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

-14 is the answer. 14x2=28-42= -14

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Evaluate the expression when z= -12<br> 1/2z^2
icang [17]

Answer:

Exact Form: z = 0, -2/25

Decimal Form: 0, -0.08

Step-by-step explanation:

I used cymath.com. I highly recommend it. It shows you the steps to the problem you want to solve!

I hope this helps! :)

The last step is to solve for z

8 0
3 years ago
3x-4y=1 and x=2y+1 using substitution
Aleksandr [31]

Answer:

x =-1

y =-1

Step-by-step explanation:

to solve this system of equation, using substiution method

3x-4y=1 ........................ equation 1

x=2y+1 ............................  equation 2

subbstitute for x into equation 1

3x-4y=1 ........................ equation 1

3(2y + 1) - 4y = 1

6y + 3 -4y = 1

2y + 3 = 1

collect the like terms

2y = 1- 3

2y= -2

divide both sides by  the coefficient of y which is y

2y/2 = -2/2

y = -1

put the value of y =-1 into equation 2

x=2y+1 ............................  equation 2

x = 2(-1) + 1

x = -2 + 1

x = -1

therefore x =-1 y = -1

3 0
4 years ago
There are 18 boys on a football team. Of the team, 1/3 of the boys are 12 years-old. Of the 12 year-olds, 1/3 have never played
kakasveta [241]

Answer:

1/9

Step-by-step explanation:

1/3 *1/3 = 1/9

8 0
3 years ago
1. Construct a table of values of the following functions using the interval of 5
Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

g(x) = \frac{x^3 + 3x - 5}{x^2}

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When x = -5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}

g(-5) = \frac{-125 -15 - 5}{25}

g(-5) = \frac{-145}{25}

g(-5) = -5.8

When x = -4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}

g(-4) = \frac{-64 -12 - 5}{16}

g(-4) = \frac{-81}{16}

g(-4) = -5.0625

When x = -3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}

g(-3) = \frac{-27 -9 - 5}{9}

g(-3) = \frac{-41}{9}

g(-3) = -4.56

When x = -2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}

g(-2) = \frac{-8 -6 - 5}{4}

g(-2) = \frac{-19}{4}

g(-2) = -4.75

When x = -1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}

g(-1) = \frac{-1 + 3 - 5}{1}

g(-1) = \frac{-3}{1}

g(-1) = -3

When x = 0

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(0) = \frac{0^3 + 3(0) - 5}{0^2}

g(0) = \frac{0 + 0 - 5}{0}

g(0) = \frac{- 5}{0}

<em>g(0) = undefined</em>

When x = 1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(1) = \frac{1^3 + 3(1) - 5}{1^2}

g(1) = \frac{1 + 3 - 5}{1}

g(1) = \frac{-1}{1}

g(1) = 1

When x = 2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(2) = \frac{2^3 + 3(2) - 5}{2^2}

g(2) = \frac{8 + 6 - 5}{4}

g(2) = \frac{9}{4}

g(2) = 2.25

When x = 3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(3) = \frac{3^3 + 3(3) - 5}{3^2}

g(3) = \frac{27 + 9 - 5}{9}

g(3) = \frac{31}{9}

g(3) = 3.44

When x = 4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(4) = \frac{4^3 + 3(4) - 5}{4^2}

g(4) = \frac{64 + 12 - 5}{16}

g(4) = \frac{71}{16}

g(4) = 4.4375

When x = 5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(5) = \frac{5^3 + 3(5) - 5}{5^2}

g(5) = \frac{125 + 15 - 5}{25}

g(5) = \frac{135}{25}

g(5) = 5.4

<em>Hence, the complete table is:</em>

x  ---- g(x)

-5 --- -5.8

-4 --- -5.0625    

-3 --- -4.56

-2 --- -4.75  

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0
3 years ago
What five-digit positive integer with an 8 in the ten-thousands place is the cube of an integer?
Sloan [31]

Answer:

44

Step-by-step explanation:

44^3 = 85,184

five digit positive

eight in the ten thousand place

4 0
3 years ago
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