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adell [148]
3 years ago
6

What type of function is shown in the table?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

its not a function it don,t grow in a normal rate

Step-by-step explanation: ur welcome

You might be interested in
Write an equation of the line that is perpendicular to y = 1/2
atroni [7]

Answer:

the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)

= -5 = -2x + 15

Step-by-step explanation:

Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5).

Using the slope intercept equation,

y = mx +c

m = slope = 1/2

For two lines to be perpendicular, the product of their slopes is -1

Let the slope of the other line be m2

m1×m2 =-1

1/2×m2 = -1

m2 = -1/(1/2) = -2

Slope of line = -2

For points (10, -5), x = 10, y =-5

-5 = -2× 10 +c

-5 = -20+ c

c = -5+20= 15

the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)

-5 = -2x + 15

6 0
4 years ago
Combine to create an equivalent expression -n + (-4) - (-4n) +6
Sav [38]

Answer: The answer is 3n + 2

Step-by-step explanation: You will have to combine like terms:

=−n + −4 + 4n + 6

=(−n + 4n) + (−4 + 6)

=3n + 2

3 0
3 years ago
Let f(x) = x2 − 16. Find f−1(x)
Yanka [14]

Answer:

f^{-1}(x)=\pm\sqrt{x+16}

Step-by-step explanation:

f(x)=x^2-16

To find the inverse of this function, temporarily the f(x) with a y (or whatever else you want) and then solve for the x.

y=x^2-16\\y+16=x^2\\x=\pm\sqrt{y+16}

Now, you can swap the variables again and write the function.

f^{-1}(x)=\pm\sqrt{x+16}

3 0
3 years ago
Calculate the slope of the line.Please help!!
vladimir2022 [97]
The slope is 2/3 you’re welcome :)
5 0
3 years ago
Help plz will give brainliest
jolli1 [7]

Answer:  5(13.5-4.5)

5(9)

=45

6 0
3 years ago
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