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Llana [10]
3 years ago
5

Brainliest to whoever can answer questions correctly ​

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0

Answer:

v ~ 32.72

Hope that helps!

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Complete ratio ... i’ll give the brainly thing
Dovator [93]
Whatever the person above said lol
7 0
3 years ago
Name the angle in four ways. Then classify the angle as acute,right,obtuse, or straight.
max2010maxim [7]

Answer:

The given angle is obtuse angle.

6 0
3 years ago
Read 2 more answers
The solution to (d+4)^2=9 is D=
Allushta [10]

Answer:

\boxed{\sf d = -1 \ \ \ or \ \ \ d = -7}

Step-by-step explanation:

\sf Solve \:  for  \: d  \: over  \: the  \: real  \: numbers: \\  \sf \implies {(d + 4)}^{2}  = 9 \\  \\  \sf Take  \: the \:  square  \: root \:  of  \: both \:  sides: \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{9}  \\  \\  \sf 9 =  {3}^{2} :   \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{ {(3)}^{2} }  \\  \\  \sf \implies d + 4 =  \pm 3 \\  \\  \sf \implies d + 4 = 3 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + 4 =  - 3 \\  \\  \sf Subtract  \: 4  \: from \:  both \:  sides:   \\ \sf \implies d + (4  - 4)= 3 - 4 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + (4 - 4) =   - 3  - 4  \\  \\ \sf \implies d =  - 1 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d  =  - 7

4 0
3 years ago
Read 2 more answers
I need help with this!
sertanlavr [38]

Answer:

67 degrees

Step-by-step explanation:

first find angle abc by subtracting 68 from 101 == 33

then add it to half of 68 (34) to get angle abe

we know it is half because if there is a bisector, both angles cbe and ebd are equal

8 0
3 years ago
Read 2 more answers
Sandra throws an object straight up into the air with initial velocity of 38 ft per square from platform that is 30 ft above the
expeople1 [14]

Answer:

3 seconds.

Step-by-step explanation:

We have been given that Sandra throws an object straight up into the air with initial velocity of 38 ft per second from platform that is 30 ft above the ground.

To find the time it will take for object to hit the ground, we will use formula:  

h(t)=-16t^2+v_0t+h_0, where, v_0 represents initial velocity and h_0 represents initial height.

Upon substituting our given initial velocity and initial height, we will get:

h(t)=-16t^2+38t+30

We know that object will hit the ground, when height will be 0, so we will equate object's height equal to 0 and solve for t as:

-16t^2+38t+30=0

Divide by 2:

-8t^2+19t+15=0

Upon using quadratic formula, we will get:

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-19\pm\sqrt{19^2-4(-8)(15)}}{2(-8)}

t=\frac{-19\pm\sqrt{361+480}}{-16}=\frac{-19\pm\sqrt{841}}{-16}

t=\frac{-19\pm29}{-16}

t=\frac{-19-29}{-16},t=\frac{-19+29}{-16}

t=\frac{-48}{-16},t=\frac{10}{-16}

t=3,t=-\frac{5}{8}

Since time cannot be negative, therefore, it will take 3 seconds for object to hit the ground.

7 0
3 years ago
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