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Semenov [28]
3 years ago
5

A student organization wondered how many hours per week college students study during a term. Each of the 10 students in the org

anization asked 10 of their friends how much they typically studied each week. A​ 95% confidence interval for the mean number of hours studied per week was​ (18,30). Are the conditions satisfied to use the confidence interval to make an inference to the population of​ interest?
Mathematics
1 answer:
Inga [223]3 years ago
4 0

Answer:

No, a convenience sample was taken.Therefore, the sample may not be representative of all college students in terms of number of hours studied per week.

Step-by-step explanation:

One of the important conditions required in other to estimate the mean of the population from the confidence interval. Requires that the data must be a random Sample. This is to ensure that sample values are not biased and as such are representative of the larger group of data.

However, in the scenario described above, the sample chose. Are friend's of the student, this makes the data lack randomness as those who aren't friends to the student do not stand a chance of being selected. The sampling procedure employed is called convenience sampling.

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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
madam [21]

The true statement is:

"The range of the function is all real numbers less than or equal to 9."

<h3>Which statements are true?</h3>

Here we have the quadratic function:

f(x) = -x^2 - 4x + 5

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

f(x) = -x^2 - 4x + 5

So the vertex is at:

x = 4/(2*-1) = -2\\

Then the y-value of the vertex is:

f(-2) = -(-2)^2 - 4*(-2) + 5 = -4 + 8 + 5 = 9

So the range is the set of all real numbers less than or equal to 9.

So the above statement is false, and the final one:

"The range of the function is all real numbers less than or equal to 9."

Is the true statement.

If you want to learn more about quadratic functions:

brainly.com/question/1214333

#SPJ1

8 0
1 year ago
Hey guys please help find the area
V125BC [204]

Answer:

70.15 ft²

Step-by-step explanation:

The figure consists of two adjacent equilateral triangles (all angles are 60 degrees and all outer edges are 9 ft).

If we focus on one of these equilateral triangles, we can get the final area by multiplying the area of that one triangle by 2.

The formula for the area of a triangle is (1/2)(base)(height).  Remembering to multiply this by 2, we get

area of figure = (base)(height)

                                             √3

                       = (9 ft)(9 ft)(--------) = (81 ft²)(1.732) = 70.15 ft²

                                               2

4 0
3 years ago
2V2 km<br> 2 km<br> X<br> A) 2V5 km<br> C) 2 km<br> B) 2V3 km<br> D) 4 km<br> HELP PLEASEE
Rasek [7]

Answer:

x=2\sqrt3\ km

Step-by-step explanation:

Given that,

The base of a triangle = 2 km

The perpendicular height of the triangle = 2\sqrt{2} \ km

We need to find the value of x. It is the Hypotenuse of the triangle. It can be solved as :

x=\sqrt{(2\sqrt{2})^2+2^2 } \\\\=2\sqrt{2+1 } \\\\=2\sqrt3\ km

So, the value of x is equal to 2\sqrt3\ km.

3 0
3 years ago
14.4% of what number is 10.4
Helga [31]
First, convert "of" to x and put this info into an equation:

Let n represent the unknown number.  

14.4 % x n= 10.4
              n = 10.4 / 14.4%
              n = 72.22222
              n = ~72

Hope this helps!
8 0
3 years ago
ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol
seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

  • The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

  • Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

  • Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

Learn more about writing equations here:

brainly.com/question/24760633

6 0
2 years ago
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