Question

Graph the equation 3x+3y=−15 using the intercepts.

Answer 1

Answer:

To find the intercepts, equate one variable to

0

and solve for the other variable:

y-intercept

Set

x

to

0

and solve for

y

giving:

3

x

−

5

y

=

15

becomes:

(

3

⋅

0

)

−

5

y

=

15

0

−

5

y

=

15

−

5

y

=

15

−

5

y

−

5

=

15

−

5

−

5

y

−

5

=

−

3

y

=

−

3

or

(

0

,

−

3

)

x-intercept

Set

y

to

0

and solve for

x

giving:

3

x

−

5

y

=

15

becomes:

3

x

−

(

5

⋅

0

)

=

15

3

x

−

0

=

15

3

x

=

15

3

x

3

=

15

3

3

x

3

=

5

x

=

5

or

(

5

,

0

)

Next. we can plot the two points on the grid:

graph{((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

Then, draw a line through the two points:

graph{(3x - 5y -15)((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}