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Svetllana [295]
2 years ago
6

In the figure below, the segments overline RS and overline RT are tangent to the circle centered at Given that OS = 3.6 and RT =

4.8 , find OR

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0

Answer:

RS = 4.8

OT = 3.6

From the Pythagorean Theorem we know:

OR^2 = ST^2 + OT^2

OR^2 = 4.8^2 + 3.6^2

OR ^2 = 23.04 + 12.96

OR^2 = 36

OR = 6

Step-by-step explanation:

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2/5 g+3h -6 when g=10 h=6
motikmotik
<h3>hello!</h3>

let's evaluate this expression

\pmb{\displaystyle\frac{2}{5}g+3h-6 }

\pmb{\displaystyle\frac{2}{5} *10+3(6)-6}

\pmb{\displaystyle\frac{2}{5} *10+18-6}

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Multiply:

\pmb{\displaystyle\frac{2}{5} *\frac{10}{1} =\frac{20}{5} =4}

Final Step:-

\pmb{4+12}

\pmb{16}

======================================================

<h3>note:-</h3>

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I'll comment and/or edit my answer :)

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