Answer: 7(-4-x) —> -28-7x. 7(4+x) —> 28+7x. -7(-4+x) —> 28-7x. -7(4-x) —> -28+7x
Step-by-step explanation:
The answer to your question is 0.008
Answer:
1.77
Step-by-step explanation:
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
The actual speed of the car is either 57 mph or 63 mph
Step-by-step explanation:
Given as :
The measured speed o the car = 60 mph
The percentage error in speedometer = 5 %
Let The actual speed of car = x mph
Now, percentage error = 
× 100
So, 
= 
or, × 60 = x - 60
Or, 3 = x - 60
∴ x = 63 mph
Hence The actual speed of the car is either 57 mph or 63 mph . Answer
