Step-by-step explanation:
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
2x²y exponit 7√6
Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
Answer:
193.53 miles
Step-by-step explanation:
Please see the diagram for understanding of how the angles were derived,
Applying Alternate Angles, ABO =77 degrees
The bearing from B to C is 192=180+12 degrees
Subtracting 12 from 77, we obtain the angle at B as 65 degrees.
We want to determine the boat's distance from its starting point.
In the diagram, this is the line AC.
Applying Law of Cosines:
The distance of the boat from its starting point is 193.53 miles (correct to 2 decimal places).
Answer:
X=4 easy blah blah blah it’s 4. jdjjdjfnfvbdnnfn
Answer:
See below.
Step-by-step explanation:
Part A:
triangle QPR and triangle PSR are similar
Part B:
Triangle QPR is a right triangle with right angle QPR.
Triangle SPR is a right triangle with right angle PSR.
Angle QPR of triangle QPR corresponds to and is congruent to angle PSR of triangle PSR.
Angle R of triangle QSR corresponds to and is congruent to angle R of triangle PSR.
The similar triangles by AA Similarity are
triangle QPR and triangle PSR
Part C:
QR/PR = PR/SR
16/PR = PR/4
PR² = 16 * 4
PR² = 64
PR = 8
