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ki77a [65]
3 years ago
9

Aaron puts several cards face down on the table. He draws one card, records the result, and then places the card back on the tab

le face down. The results of his experiment are shown below.
outcome frequency
10 4
jack 0
queen 3
king 2
ace 1


Based on the results, what is the probability of choosing a 10 or Jack from the cards?
Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
4/10 if he put down 10 cards total
Bad White [126]3 years ago
3 0
For choosing jack answer maybe 1/4 as there are 4 cards of jack and for 1 draw he has 1 chance so 1/4
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observa con atencion los siguientes desarrollos planos y encierra con cual de ellos se puede armar cada cuerpo uno de ellos tien
Viefleur [7K]

Answer:

Can you give it in a english

Step-by-step explanation:

7 0
3 years ago
Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o
NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so \pi = 0.8.

(a) What is the probability she gets an A?

There are four problems, so n = 4

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find P(X \geq 3)

P(X \geq 3) = P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096

P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096

P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so n = 3

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find P(X \geq 2)

P(X \geq 3) = P(X = 2) + P(X = 3)

P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384

P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512

P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0
4 years ago
There are 321 crayons in a box and 204 crayons on the floor. About how many fewer than 1,000 crayons are there? Estimate. Then s
Sati [7]

Answer:

See below

Step-by-step explanation:

<u>The estimated number:</u>

  • 300 + 200 = 500

<u>The difference between the estimated number an 1000 is:</u>

  • 1000 - 500 = 500

<u>The exact number:</u>

  • 321 + 204 = 525

<u>The difference between the exact number and 1000 is:</u>

  • 1000 - 525 = 475
6 0
3 years ago
a helicopter is hovering above a road at an altitude of 24 m. At a certain time, distance between the helicopter and a car on th
SCORPION-xisa [38]
Arcsin(8/15), since the sine is 24m/45m=8/15.
6 0
3 years ago
Read 2 more answers
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
3 years ago
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