Question

A 1.0 x 10^2-kilogram box rests on the bed of a

Answer 1

Answer:

$2\times 10^2\ \text{N}$

Explanation:

$\mu$ = Coefficient of friction

g = Acceleration due to gravity

m = Mass of box = $1\times 10^2\ \text{kg}$

a = Acceleration of the block = $2\ \text{m/s}^2$

Acceleration is given by

$a=\mu g\\\Rightarrow \mu=\dfrac{a}{g}$

Friction force is given by

$f=\mu mg\\\Rightarrow f=\dfrac{a}{g}mg\\\Rightarrow f=ma\\\Rightarrow f=1\times 10^2\times 2\\\Rightarrow f=2\times 10^2\ \text{N}$

The magnitude of the force of friction on the box as it moves with the truck without slipping is $2\times 10^2\ \text{N}$.