SOS:
The answers is:
In a dihybrid cross, the F2 will have nine genotypes, but only four phenotypes because the <u><em>Heterozygous</em></u> genes cause the <u><em>Dominant</em></u> traits to mask the <u><em>Recessive</em></u> traits.
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Answer:
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
Explanation:
Given that:
The allele → R = Red beetles
The allele → B = Blue beetles
Since the gene color shows a codominant allele
The Red Beetle = RR
The blue beetles will be = BB
The heterozygous beetle will be = RB
∴
The punnet square showing the crossing of RB × RR is:
R B
R RR RB
R RR RB
The result shows that we have two red beetles and two heterozygous beetles.
Hence;
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
The answer is A. Man-made
