3 years ago

Please answer :) ( Will give brainlst)

Mathematics

1 answer:

denis-greek [22]3 years ago

6 0

Answer:

3. c 4. b 5. a

Step-by-step explanation:

i did the math

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The vertex form of the equation of a parabola is y = 2(x+ 4)2 - 21.

Ivanshal [37]

Answer:

y = 2x² + 16x + 11

Step-by-step explanation:

first foil (x + 4)² to get x² + 8x + 16

distribute 2 to get 2x² + 16x + 32

subtract 21 from 32

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3 years ago

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1 year ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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3 years ago

What is the value of the expression?

lora16 [44]

-square root 3 over 3
hope this helps.

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3 years ago

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RoseWind [281]

Answer:

Step-by-step explanation:

Given

2x² - y ← substitute x = 3 and y = - 2 into the expression

= 2(3)² - (- 2)

= 2(9) + 2

= 18 + 2

= 20

6 0

3 years ago

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