Please answer :) <br><br> ( Will give brainlst)

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago

PLS ANSWER FAST, WILL GIVE BRAINLIEST

valentina_108 [34]

Answer:

I guess option c is the answer

4 0

3 years ago

Hmm, I need someone to answer this. Just answer it right, if you don't know it then don't answer, It's annoying. It's probably r

Phoenix [80]

Answer:

Step-by-step explanation:

A)

f(s)=2s+25 and s(w)=25w

f(w)=2(25w)+25

f(w)=50w+25

B)

The ujits for the composite function are f=number of flowers and w=number of weeks.

C)

f(30)=50(30)+25

f(30)=1500+25

f(30)=1525

3 0

3 years ago

May someone help me out with this please

Fiesta28 [93]

First we find the mean (average)
(7 + 8 + 9 + 9 + 10 + 11)/6 = 54/6 = 9

now we subtract the mean from every data number....and square it
7 - 9 = -2...-2^2 = 4
8 - 9 = -1...-1^2 = 1
9 - 9 = 0....0^2 = 0
9 - 9 = 0...0^2 = 0
10 - 9 = 1....1^2 = 1
11 - 9 = 2....2^2 = 4

now we find the mean (average) for those numbers
(4 + 1 + 0 + 0 + 1 + 4) / 6 = 10/6 = 1.67...this is the variance

to find the standard deviation, take the sqrt of the variance
sqrt 1.67 = 1.29 <== ur answer

7 0

3 years ago

A box contains 5 blue beads, 4 yellow beads and 3 purple beads.

Gennadij [26K]

Answer:

A: 1/22

B: 3/44

C: 41/44

D: 3/11

Step-by-step explanation:

Hope this help : )

7 0

3 years ago

Please answer :) ( Will give brainlst)