Answer:
042
Step-by-step explanation:
682 has one correct placement this is the 2 becuase if we look at the 206 one we can see that the 6 is wrongly placed and 614 has one number wrongly placed, so it means that 2 is in the correct spot in 682.
Next, we can look at 206 and since we know the 2 is one of the values and 6 isn't, that leaves the 0.
Finally, we can eliminate al values of 7, 3, 8 because they are not correct. This leaves us with either 1 or 4 as the remaining variables. We know that we need the middle value, so that eliminates the 1.
To clarify this more, the code is 042.
Based on clue #1 and #2, we can say that 6 is not the correct number.
Now we know that the unlock code does not contain 6 and based on clue #3, we know that 2 and 0 are correct numbers but in the wrong position. From clue #1, 2‘s position should be on the right. The code is ??2.
Based on clue #5, 0‘s position should be on the left. The code is 0?2.
We have to find the missing number in the middle position. Based on clue #2, the middle number has to be 4. It cannot be 1, as the statement says that the number is wrongly placed.
We are left with 042.
In the attached, the blanks correspond to zeros.
Answer:
The scale factor used to go from P to Q is 1/4
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
If two figures are similar, then the ratio of its areas i equal to the scale factor squared
Let
z ----> the scale factor
x -----> area of polygon Q
y -----> area of polygon P
![z^{2}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![y=72\ units^2](https://tex.z-dn.net/?f=y%3D72%5C%20units%5E2)
<em>Find the area of polygon Q</em>
Divide the the area of polygon Q in two triangles and three squares
The area of the polygon Q is equal to the area of two triangles plus the area of three squares
see the attached figure N 2
<em>Find the area of triangle 1</em>
![A=(1/2)(1)(2)=1\ units^2](https://tex.z-dn.net/?f=A%3D%281%2F2%29%281%29%282%29%3D1%5C%20units%5E2)
Find the area of three squares (A2,A3 and A4)
![A=3(1)^2=3\ units^2](https://tex.z-dn.net/?f=A%3D3%281%29%5E2%3D3%5C%20units%5E2)
<em>Find the area of triangle 5</em>
![A=(1/2)(1)(1)=0.5\ units^2](https://tex.z-dn.net/?f=A%3D%281%2F2%29%281%29%281%29%3D0.5%5C%20units%5E2)
The area of polygon Q is
![x=1+3+0.5=4.5\ units^2](https://tex.z-dn.net/?f=x%3D1%2B3%2B0.5%3D4.5%5C%20units%5E2)
Find the scale factor
![z^{2}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![y=72\ units^2](https://tex.z-dn.net/?f=y%3D72%5C%20units%5E2)
![x=4.5\ units^2](https://tex.z-dn.net/?f=x%3D4.5%5C%20units%5E2)
substitute and solve for z
![z^{2}=\frac{4.5}{72}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7B4.5%7D%7B72%7D)
![z^{2}=\frac{1}{16}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B16%7D)
square root both sides
![z=\frac{1}{4}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B1%7D%7B4%7D)
therefore
The scale factor used to go from P to Q is 1/4
Hello! the answer to your question is that
p = 48
Answer:
We have a direct variation. Distance, D, varies directly as time, t.
So D = Kt where K is the constant. In this case, speed. So D = Kt is our constant of variation.
If D = 150 miles and t = 4 hours
Then we have 150 = K (4)
K = 150/4 = 37.5. The constant of variation is 37.5.
If you keep traveling at a constant speed K = 37.5 and D = 200. We have
200 = 37.5 * t
t = 200/37.5 = 5.333 hours.
Step-by-step explanation:
n simple terms its / D=KT / 37.5 / 5.3