Answer:
Step-by-step explanation:
Let the price for children and adults package be represented with x and y respectively.
For the first week the sum of the package will be as follows:
3x+8y = 126
For the two weeks after:
6x+4y= 108
So, we will be having two equations
3x+8y = 126..... (1)
6x+4y= 108.......(2)
These are simultaneous equations
From equation 1
3x+8y = 126
3x = 126-8y
X = 126-8y/3 ............. (3)
Put equation 3 into 2
6 ( 126-8y)/3 +4y = 108
756-48y/3 +4y = 108
756-48y+12y/3 = 108
Cross multiplying
756-48y+12y= 108×3
756-48y+ 12y = 324
Collecting like terms
756-324 = 48y-12y
432= 36y
Divide both sides by 36
432/36 = 36y/36
y= 12
Substituting y into equation 1
3x+8= 126
3x+96=126
3x= 126-96
3x= 30
Divide both sides by 3
3x/3 = 30/3
x = 10
Hence for each of the packages for children and adults. It will be 10 and 12 respectively.
correct Option is B i.e, 
whose simplified form is: 
Step-by-step explanation:
We need to solve the expression:
![2[(6x)(6x)]+4[(12x - 9)(6x)]](https://tex.z-dn.net/?f=2%5B%286x%29%286x%29%5D%2B4%5B%2812x%20-%209%29%286x%29%5D)
Solving:
![2[(6x)(6x)]+4[(12x - 9)(6x)]\\=2[36x^2]+4[(12x*6x)-(9*6x)]\\=72x^2+4[72x^2-54x]\\=72x^2+288x^2-216x\\=360x^2-216x](https://tex.z-dn.net/?f=2%5B%286x%29%286x%29%5D%2B4%5B%2812x%20-%209%29%286x%29%5D%5C%5C%3D2%5B36x%5E2%5D%2B4%5B%2812x%2A6x%29-%289%2A6x%29%5D%5C%5C%3D72x%5E2%2B4%5B72x%5E2-54x%5D%5C%5C%3D72x%5E2%2B288x%5E2-216x%5C%5C%3D360x%5E2-216x)
So, correct Option is B i.e, whose simplified form is:
Keywords: Surface area of the rectangular prism
Learn more about surface area of the rectangular prism at:
#learnwithBrainly
Answer:
-8y = 3x
Step-by-step explanation:
<span><span>I think the answers are:
Statement Reason</span><span><span><span>
<span>12=<span>13</span>x+5 </span></span>Given</span><span><span>
<span>7=<span>13</span>x </span></span>Subtraction Property of Equality</span><span><span>
21 = x </span>Multiplication Property of Equality</span><span><span>
x = 21 </span><span>Symmetric Property of Equality
By the way, I'm doing the same exam for Geometry as well. There's a lot of proof questions on there which I'm not good at doing for the reasoning part. If you finish the exam before I do, maybe you can message me what the answers are for some of the questions on there so I know if my answers for the questions are incorrect or not.
Besides that, hope the answer above is correct for you.
<em>~ ShadowXReaper069</em></span></span></span></span>
