A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
Step-by-step explanation:
1) let the number=x
six times a number=6x
Condition:
6x+4=22
2) eleven times a number=11x
Condition:
11x-5=50
3) 9 times a number=9x
Condition:
9x-7=-16
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area of triangle = 1/2(3)(4) = 6 in^2
area of rectangle = 3 x 10 = 30 in^2
area of trapezoid = 1/2(3+5)(2) = 8 in^2
area of the figure: 6 in^2 + 30 in^2 + 8 in^2 = 44 in^2
answer
44 in^2
Answer:
Step-by-step explanation:
(cos 4a*cos 2a+sin 4a*sin 2a)/sin 4a
=[cos (4a-2a)]/sin 4a
=(cos 2a)/sin 4a
=(cos 2a) /(2 sin 2a cos 2a)
=1/(2 sin 2a)
=1/2 csc 2a
