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Cloud [144]
3 years ago
12

Pls help!!! Which list of numbers is ordered from greatest to least?

Mathematics
1 answer:
Anettt [7]3 years ago
6 0
B

It’s the only answer that begins with a positive number
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Y = -3x+4 and y= 1/2x-3
Papessa [141]

Answer:

{x = 2  , y = -2

Step-by-step explanation:

Solve the following system:

{y = 4 - 3 x | (equation 1)

{y = x/2 - 3 | (equation 2)

Express the system in standard form:

{3 x + y = 4 | (equation 1)

{-x/2 + y = -3 | (equation 2)

Add 1/6 × (equation 1) to equation 2:

{3 x + y = 4 | (equation 1)

{0 x+(7 y)/6 = (-7)/3 | (equation 2)

Multiply equation 2 by 6/7:

{3 x + y = 4 | (equation 1)

{0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{3 x+0 y = 6 | (equation 1)

{0 x+y = -2 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 2 | (equation 1)

{0 x+y = -2 | (equation 2)

Collect results:

Answer:  {x = 2  , y = -2


8 0
3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
lidiya [134]
Recall your d = rt,  distance = rate * time.

notice, the distance are the same, say it was "d" miles.

and if car A is travelling at a speed of say "r" mph, then B is going at "r+15" mph.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Car A}&d&r&2\\
\textit{Car B}&d&r+15&1.5
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=2r\\
d=1.5(r+15)\\
----------\\
\boxed{2r}=1.5(r+15)
\end{cases}
\\\\\\
2r=1.5r+22.5\implies 0.5r=22.5\implies r=\cfrac{22.5}{0.5}\implies \boxed{r=\stackrel{mph}{45}}

how far is B going?  well, r + 15.
5 0
3 years ago
Read 2 more answers
Simplify: 2x + 9 - 17x - 15 -x​
Ostrovityanka [42]

Answer:

1

Step-by-step explanation:

2x + 9 - 17x - 15 - x =????

2x - 17x - x + 9 - 15 = 0

- 15x - x - 16 = 0

- 16x - 16 =0

-16x = 16

x = 16 / - 16

x = 1

6 0
3 years ago
Find the exact solution to the equation 10-log8(x+2)=9
ohaa [14]

Answer:

-0.89269063 ...

Step-by-step explanation:

Put it in the calculator

8 0
3 years ago
A ribbon is 4 m long. How many pieces each 30 cm long can be cut from the ribbon?​
EleoNora [17]

Answer:

13 pieces

Step-by-step explanation:

First we convert 4m into cm :

1m = 100cm

4m = 400cm

Now we need to figure out how many 30s go into 400 :

400 ÷ 30 = 13 remainder 10

So 13 pieces can be cut from the ribbon

Hope this helped and have a good day  

5 0
2 years ago
Read 2 more answers
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