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poizon [28]
3 years ago
14

Pls help with this one I will give you brainliest thank you!

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

\boxed{Volume \: of \: right \:  rectangular \: prism = 790 \: {meter}^{3}}

Explanation:

Volume of right rectangular prism is same as volume of cuboid

Length = 22.9 meters

Width = 7.5 meters

Height = 4.6 meters

Volume of right rectangular prism = Length × Width × Height

= 22.9 × 7.5 × 4.6

= 22.9 × 34.5

= 790.05 meter³

= 790 meter³

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Rolling an even number (2, 4 or 6) is an event, and rolling an odd number (1, 3 or 5) is also an event. In Experiment 1 the probability of each outcome is always the same. The probability of landing on each color of the spinner is always one fourth.
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Five and one half of 2 and one third is what number?
labwork [276]

Given:

Five and one half of 2 and one third.

To find:

The number for the given statement.

Solution:

Five and one half = 5\dfrac{1}{2}

2 and one third = 2\dfrac{1}{3}

The given statement is five and one half of 2 and one third.

Here, the word "of" is used for multiplication.

So, the expression for the given statement is:

5\dfrac{1}{2}\times 2\dfrac{1}{3}

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Therefore, the required number is \dfrac{77}{6}.

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1/3(x - 10) = - 4<br><br> x = ?
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Answer:

x = -2

Step-by-step explanation:

1/3(x - 10) = - 4

1/3x - 10/3 = - 4

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In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

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P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

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