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3 years ago

Represent the arithmetic series using the recursive formula 94, 87, 80, 73,

Mathematics

1 answer:

Rama09 [41]3 years ago

5 0

Answer:

$a_1 = 94 \\ a_n = a_ {n - 1} - 7$

Step-by-step explanation:

The given arithmetic sequence is 94, 87, 80, 73,...

The first term is

$a_1=94$

The common difference is

$d = 87 - 94$

$d = - 7$

The recursive formula is given by:

$a_n = a_ {n - 1} + d$

We substitute the common difference to obtain:

$a_n = a_ {n - 1} - 7$

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ANSWER:

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Question b):

$\dfrac{5}{3}\div{x}= \dfrac{10}{9}\\ \\ \\ \dfrac{5}{3}\div{ \dfrac{x}{1} }= \dfrac{10}{9}\\ \\ \\ \dfrac{5*1}{3*x}= \dfrac{10}{9}\\ \\ \\ \dfrac{5}{3x}= \dfrac{10}{9}\\ \\9(5)=10(3x)\\ \\45=30x\\ \\ \dfrac{45}{30}=x\\ \\ \\ \dfrac{\not{45}}{\not{30}}=x\\ \\ \\ \dfrac{3}{2}=x\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

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3 years ago

Subtract, Write the result in the form a+bi<br><br> (5-2i )ñ (6+8i)

Vedmedyk [2.9K]

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8 0

4 years ago

Read 2 more answers

-4 1/3 + 5 2/3 <br> step by step

Dominik [7]

Answer:

1 1/3

Step-by-step explanation:

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= { (-13) + 17 } / 3

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= 1 1/3

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3 years ago

Morita works in a florist shop and makes flower arrangements. She puts 10 flowers in each vase and 2/10 of the flowers are daisi

Delvig [45]

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3 years ago

a rectangle field has an anrea of 40cm^2. if one side of the field is 3m longer than the other side, find the new area of the fi

oksian1 [2.3K]

The area of the field where the length of each side is increased by 10% is 48.4 $cm^{2}$ .

Step-by-step explanation:

The given is,

A rectangle field has an area of 40 $cm^{2}$

If one side of the field is 3 cm longer than the other side

The length of new area in each side is increased by 10%

Step:1

Let,

$b$ - One side of rectangle

$l$ - Other side of rectangle

From given.

$l$ - $b$ +3

Formula for area of rectangle,

$Area, a = lb$

40 = ( b+3) × b

40 = $b^{2}$ + 3b

Solving the above the equation,

b = 5 cm

l = 8 cm

Step:2

If the area of rectangle increased by 10%,

l = 8 + ( 8 × $\frac{10}{100}$ )

= 8.8

b = 5 + ( 5 × $\frac{10}{100}$ )

= 5.5

Area of rectangle is,

a = ( 8.8 × 5.5 )

= 48.4 square centimeters

Result:

The area of the field where the length of each side is increased by 10% is 48.4 $cm^{2}$ , if a rectangle field has an area of 40 square centimeters and one side of the field is 3 cm longer than the other side.

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3 years ago