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wolverine [178]
2 years ago
11

A group of friends go out for a meal and the meal costs £148.

Mathematics
1 answer:
statuscvo [17]2 years ago
5 0
148 x 0.25= 37

you would multiply by the percent off they get.
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A system of equations is graphed on the coordinate plane. y=−6x−3y=−x+2 What is the solution to the system of equations? Enter t
Mamont248 [21]
If you equate both, the y is eliminated:

-6x-3 = -x+2

Simplify this to find x:

-5x = 5
x = -1

Fill in x=-1 in either equation:

y = --1 + 2 = 3

So (-1,3) is the solution, it is where the lines intercept.
6 0
3 years ago
Read 2 more answers
Find the product of the complex number and it's conjugate. <br><br> 9-5i
Dennis_Churaev [7]
Conjugate of 9-5i is 9+5i
product of those two: (9-5i)*(9+5i) = 9^{2} - (5i)^{2} =81-25* i^{2} =81-25*(-1)=81+25=106
3 0
3 years ago
What is being done to the variable in the equation = -40?
larisa86 [58]

Answer:

It's being divided by 5.

Step-by-step explanation:

In this question, the variable being used in the equation is being divided by 5. This is represented by the / symbol in the equation which is the symbol for division. If we multiply both sides by 5 we can isolate the variable M and get its value like so...

M/5 = -40   ... multiply both sides by 5

M = -200

Therefore in this scenario, the value of M would be -200

7 0
3 years ago
WIL GIVE BRAINLIEST IF ANSWER FAST! Evaluate the expression 7x2y, when x = 4 and y = 2. 112 224 542 718
avanturin [10]

Answer:

224

Step-by-step explanation:

Substitute x = 4 and y = 2 into the expression and evaluate

7x²y = 7 × 4² × 2 = 7 × 16 × 2 = 7 × 32 = 224.

Hope this helped you!

4 0
3 years ago
What would be the missing values for this
sergiy2304 [10]

Given:

$x^{2} y^{8} \cdot \frac{x^{3} y^{?}}{x y^{3}}=x^{4} y^{2}

To find:

The missing value.

Solution:

Let the missing value be m.

$x^{2} y^{8} \cdot \frac{x^{3} y^{m}}{x y^{3}}=x^{4} y^{2}

Using exponent rule: a^m \cdot a^n=a^{m+n}

$ \frac{x^{2+3} y^{8+m}}{x y^{3}}=x^{4} y^{2}

$ \frac{x^{5} y^{8+m}}{x y^{3}}=x^{4} y^{2}

Using exponent rule: \frac{a^m}{a^n} =a^{m-n}

$ x^{5-1} y^{8+m-3}=x^{4} y^{2}

$ x^{4} y^{5+m}=x^{4} y^{2}

Equate x terms and y terms.

x^4=x^4 and y^{5+m}=y^2

If the bases are same, then the powers are equal.

5+m=2

Subtract 5 from both sides.

5+m-5=2-5

m=-3

The missing value is -3.

7 0
3 years ago
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