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kow [346]
3 years ago
8

Please help me with my assignment ​

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
-50 and +50

Not 100% sure
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Evaluate the expression for p=3.<br><br> 4p=
Arada [10]

Answer:

12

Step-by-step explan

4 0
3 years ago
Read 2 more answers
Pls help me with 4 and 5 and explain how u did it
marta [7]
In the same way, the x<span>-axis is also the line "y = 0". Then, algebraically, an </span>x-intercept is a point on the graph where y is zero, and. a y-intercept<span> is a point on the graph where </span>x<span> is zero.
Honestly I didn't get it either but I hope this helped ^ ^</span>
5 0
3 years ago
Using the image below, identify the angles that are vertical angles, list the angles that are linear pairs, and then solve for ,
34kurt

Answer:

Step-by-step explanation:

y and 76 are vertically opposite angles

x and z are vertically opposite angles

Linear pairs.

If sum of two adjacent angles are 180, then they are linear pair.

x & 76 are linear pairs

y & z are linear pairs

z & 76 are linear pairs

x and y are linear pairs

Solutions:

y = 76   { vertically opposite angles are equal}

x + 76 = 180  { linear pair}

x = 180 - 76

x = 104

z = x  {Vertically opposite angles are equal}

z = 104

6 0
3 years ago
In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x,
Tomtit [17]

To approximate the volume with 8 boxes, we have to split up the interval of integration for each variable into 2 subintervals, [0, 1] and [1, 2]. Each box will have midpoint m_{i,j,k} that is one of all the possible 3-tuples with coordinates either 1/2 or 3/2. That is, we're sampling f(x,y,z)=\cos(xyz) at the 8 points,

(1/2, 1/2, 1/2)

(1/2, 1/2, 3/2)

(1/2, 3/2, 1/2)

(3/2, 1/2, 1/2)

(1/2, 3/2, 3/2)

(3/2, 1/2, 3/2)

(3/2, 3/2, 1/2)

(3/2, 3/2, 3/2)

which are captured by the sequence

m_{i,j,k}=\left(\dfrac{2i-1}2,\dfrac{2j-1}2,\dfrac{2k-1}2\right)

with each of i,j,k being either 1 or 2.

Then the integral of f(x,y,z) over B is approximated by the Riemann sum,

\displaystyle\iiint_B\cos(xyz)\,\mathrm dV\approx\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos m_{i,j,k}\left(\frac{2-0}2\right)^2

=\displaystyle\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos\frac{(2i-1)(2j-1)(2k-1)}8

=\cos\dfrac18+3\cos\dfrac38+3\cos\dfrac98+\cos\dfrac{27}8\approx\boxed{4.104}

(compare to the actual value of about 4.159)

4 0
3 years ago
This doesn’t make sense explain plz
AnnZ [28]

Its simple, graph them.

For the first equation, go on the Y-Axis (the vertical one) and go to 4. Then from there go up 1, right 6.

For the second equation go on the Y-Axis (the vertical one) and plot a point at 1 (aka 0,1) Now you go up 1, right 3.

When you see an equation like y=2x+3, the 3 represents the point (0,3) as when the x is 0, y=3. Just plug the numbers in. And as for the "2x" 2 is the slope. Slope is always rise/run or up, then right. So if its 2 your slope is 2/1, rise 2, over 1. If it "-2x" is your slope then all you have to do is go down 2, right 1.

I hope this cleared up your confusion, brainliest/heart would help.

5 0
3 years ago
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