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kow [346]
3 years ago
8

Please help me with my assignment ​

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
-50 and +50

Not 100% sure
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Jules is measuring a patient’s height at 4 feet What is this height in inches? Answer
kondor19780726 [428]

Answer:

48 inches

Step-by-step explanation:

There are 12 inches in 1 foot. So multiply by 12 to convert from feet to inches.

4 × 12 = 48

4 feet = 48 inches

3 0
2 years ago
A survey found that 89% of a random sample of 1024 American adults approved of cloning endangered animals. Find the margin of er
Kobotan [32]

Answer:

The margin of error for the survey is 0.016

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1024

Sample proportion:

\hat{p} = 89\% = 0.89

We have to find the margin of error associated with a 90% Confidence interval.

Formula for margin of error:

z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.10} = 1.64

Putting the values, we get:

M.E = 1.64\times (\sqrt{\dfrac{0.89(1-0.89)}{1024}})\\\\M.E=0.016

Thus, the margin of error for the survey is 0.016

3 0
3 years ago
Boyle’s law states that the volume of a gas varies inversely with applied pressure. Suppose the pressure on 60 cubic meters of g
tatyana61 [14]
\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \stackrel{\textit{the volume of a gas varies inversely with applied pressure}}{v=\cfrac{k}{p}}
\\\\\\
\textit{we also know that }
\begin{cases}
v=60\\
p=1
\end{cases}\implies 60=\cfrac{k}{1}\implies 60=k
\\\\\\
\boxed{v=\cfrac{60}{p}}
\\\\\\
\stackrel{\textit{now if we apply 3 atmospheres, p=3, what is \underline{v}?}}{v=\cfrac{60}{3}}
8 0
4 years ago
Read 2 more answers
An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
3 years ago
A meal costs $30 before tax and tip.
Korolek [52]

Answer:

33.48

Step-by-step explanation:

30*0.07=2.10

30-2.10=27.90

27.90*0.20=5.58

27.90+5.58

33.48

5 0
3 years ago
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