Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
1/20x52/1=52/20 which equals to your answer that is 2 3/5
The volume of a sphere of radius r is given by
For your given conditions, the volume of 1/2 a sphere becomes
Seems to match your 2nd choice:
... 1 over 24 over 322 over 7(83)
Answer:
11/6 or decimal 1.8333... + 4.9 = 6.733333....
Step-by-step explanation:
Simplify the following:
(3 + 2/3)/2
Express 4/6 in its lowest form by cancelling out gcd(4, 6) = 2 from the numerator and denominator. 4/6 = (2×2)/(2×3) = 2/3:
(2/3 + 3)/2
Put 3 + 2/3 over the common denominator 3. 3 + 2/3 = (3×3)/3 + 2/3:
((3×3)/3 + 2/3)/2
3×3 = 9:
(9/3 + 2/3)/2
9/3 + 2/3 = (9 + 2)/3:
((9 + 2)/3)/2
9 + 2 = 11:
(11/3)/2
11/3×1/2 = 11/(3×2):
11/(3×2)
3×2 = 6:
Answer: 11/6 or decimal 1.8333... + 4.9 = 6.733333....
Answer:
Answer is B hope this helps
Step-by-step explanation:
