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Vaselesa [24]
3 years ago
14

Toward an Artificial Cell Scientists have recently constructed an artificial ribosome in vitro from purified ribosomal proteins

and rRNAs. (Some of the following questions may require sleuthing in earlier chapters to answer.) What types of intermolecular forces do you think are holding the individual proteins and rRNAs together in this macromolecular complex
Biology
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

RNAs and proteins can bind via electrostatic interactions, hydrophobic interactions, Hydrogen bonding interactions and base stacking interactions

Explanation:

Proteins bind to nucleic acids (i.e., both DNA and RNA) through different types of interactions:

- electrostatic interactions, also known as van der Waals interactions, refer to attractive/repulsive interactions between molecules depending on their electric charges.

- hydrophobic interactions, i.e., interactions between nonpolar molecules and water molecules

- Hydrogen bonding interactions resulting from the interaction between a hydrogen (H) atom that bind to an electronegative atom (e.g., N, O, F, etc), and another electronegative atom.

- base stacking interactions that result from the arrangement of RNA nucleotides

In this case, it is also important to highlight that the interaction will depend on the specific tertiary structure of ribosomal proteins and ribosomal RNAs (rRNAs).

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Obesity can lead to what disease in which there is excess sugar in the blood
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Explanation:

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The skeletal and muscular systems are similar because
AveGali [126]

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3 years ago
suppose you balanced a sample against three 10-gram masses. Suppose the sample weighed a little more than three masses, but coul
alexdok [17]

Answer: 241.5

Explanation:

Move the slider on the 100 gram beam to the first mark on the right, which is the 100 gram mark. If the pointer still is above the central mark, continue to move the slider to the right. Once the pointer drops below the central mark, move the slider back to the previous mark to the left. If the pointer drops below the central mark at 100 grams, move the slider back to zero.

Move the slider on the 10 gram beam to the 10 gram mark. Perform the same adjustments you did in the previous step until you find the appropriate slot for the 10 gram slider.

Repeat the same process with the 1 gram slider.

Add the values from each slider. For instance, if the 100 gram slider is on 200, the 10 gram slider is on 40 and the 1 gram slider is on 1.5, you would add 200 plus 40 plus 1.5 to get a total of 241.5 grams as the mass of your object in the tray.

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