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3 years ago

A sweatshirt was on sale for 32% off and cost $40.80 without tax. What was the original price of the

Mathematics

2 answers:

Dovator [93]3 years ago

8 0

Answer:

$60

Step-by-step explanation:

x-0.32x=40.8

0.68x=40.8

x=60

Crank3 years ago

5 0

Answer: The original cost of the sweatshirt would be $60 because

x-0.32x=40.8

0.68x=40.8

x=60

Hope this helps :) please mark Brainliest

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3 = logb(512)<br><img src="https://tex.z-dn.net/?f=%20log_%7Bb%7D%28512%29%20" id="TexFormula1" title=" log_{b}(512) " alt=" log

zzz [600]

Answer:

Step-by-step explanation:

$\text{Use}\ \log_ab=c\iff a^c=b,\ \text{for}\ a>0,\ b>0\ \wedge\ a\neq1\\\\Domain:b>0\ \wedge\ b\neq1\\\\\log_b(512)=3\iff b^3=512\to b=\sqrt[3]{512}\\\\\begin{array}{c|c}512&2\\256&2\\128&2\\64&2\\32&2\\16&2\\8&2\\4&2\\2&2\\1\end{array}\\\\512=2^9=2^{3\cdot3}=(2^3)^3=8^3\\\\\text{Therefore}\ b=\sqrt[3]{512}=\sqrt[3]{8^3}=8\in D$

$\text{Used:}\\\\(a^n)^m=a^{nm}\\\\\sqrt[n]{a^n}=a$

6 0

3 years ago

Which facts are true about f(x)=log8^x?

Veseljchak [2.6K]

F(x) = log8^x = xlog8 - it's a linear function

TRUE
A. It is Increasing because a = log8 > 0

6 0

3 years ago

Based on historical data, your manager believes that 26% of the company's orders come from first-time customers. A random sample

scoundrel [369]

Answer:

$\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})$

And we can use the z score formula given by:

$z = \frac{\hat p -\mu_p}{\sigma_p}$

And if we find the parameters we got:

$\mu_p = 0.26$

$\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349$

And we can find the z score for the value of 0.4 and we got:

$z = \frac{0.4-0.26}{0.0349}= 4.0119$

And we can find this probability:

$P(z>4.0119) = 1-P(z$

And if we use the normal standard table or excel we got:

$P(z>4.0119) = 1-P(z$

Step-by-step explanation:

For this case we have the following info given:

$p = 0.26$ represent the proportion of the company's orders come from first-time customers

$n=158$ represent the sample size

And we want to find the following probability:

$p(\hat p >0.4)$

And we can use the normal approximation since we have the following two conditions:

1) np = 158*0.26 = 41.08>10

2) n(1-p) = 158*(1-0.26) = 116.92>10

And for this case the distribution for the sample proportion is given by:

$\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})$

And we can use the z score formula given by:

$z = \frac{\hat p -\mu_p}{\sigma_p}$

And if we find the parameters we got:

$\mu_p = 0.26$

$\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349$

And we can find the z score for the value of 0.4 and we got:

$z = \frac{0.4-0.26}{0.0349}= 4.0119$

And we can find this probability:

$P(z>4.0119) = 1-P(z$

And if we use the normal standard table or excel we got:

$P(z>4.0119) = 1-P(z$

8 0

3 years ago

If A and B are mutually exclusive then: (A) P(A/B) = 0 (B) P(A/B) =P(B) (C) P(A or B) = 0 (D) P(A/B) = P(A) (E) none of the abov

Elis [28]

Answer:

Step-by-step explanation:

Two events are termed to be mutually exclusive if they cannot happen at the same time. This means that the probability of occurring at the same time is zero.

A is correct.

The probability of the two events happening at the same time is zero

B is incorrect

The probability of both happening at the same is not equal to the probability of B alone

C is incorrect

The probability of the union of the two is never equal to zero since they might occur at different times

D. Is incorrect

The probability of both happening at the same time is never equal to the probability of A alone

3 0

3 years ago

Prove that the median to the base of an isosceles triangle is also: the altitude to the base.

EleoNora [17]

Hey there!

The base angles theorem converse states if two angles in a triangle are congruent, then the sides opposite those angles are also congruent. The Isosceles Triangle Theorem states that the perpendicular bisector of the base of an isosceles triangle is also the angle bisector of the vertex angle.

Let me know if you are still confused and need a better explination :)

Have a great day!

7 0

3 years ago

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