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2 years ago

Teachers who give group grades on school projects encourage teamwork amongst students. Is this a strong or weak claim?

Mathematics

1 answer:

mezya [45]2 years ago

7 0

<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ Personally, I would say it is a weak claim. Most of the times that teachers assign group work, it tends to be done by a few people while the others do nothing or very little.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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marysya [2.9K]

None of these options seem to be correct. You can check each result by differentiation:

$(e^x\sec^2x)'=e^x(\sec^2x+2\sec^2\tan x)=e^x\sec^2x(1+\tan x)$

$(e^x\sec x)'=e^x(\sec x+\sec x\tan x)=e^x\sec x(1+\tan x)$

$(e^x\tan^2x)'=e^x(\tan^2x+2\tan x\sec^2x)=e^x\tan x(\tan x+2\sec^2x)$

$(e^x\tan x)'=e^x(\tan x+\sec^2x)$

But none of these are equivalent to $e^x(\sec x+\tan^2x)$ ...

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2 years ago

If : f(x)=x^2, g(x)=x-1. Find (f×g)(x).<br>

kramer

Answer:

$\boxed{ f\cdot{g}(x) = x {}^{3} - x {}^{2}}$

Step by step explanation:

Given that,

$f(x) = {x}^{2}$

$g(x) = x - 1$

Solution:

Solving for (f•g)(x):

$= f(x) \cdot g(x)$

Now substitute the given values.

$= x {}^{2} \cdot(x - 1)$

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Apply distributive property:

$= (x ^{2} \cdot x) - x {}^{2} \cdot 1$

$\boxed{ f\cdot{g}(x) = x {}^{3} - x {}^{2}}$

Hence,f•g(x) will be $x {}^{3} - x {}^{2}$ .

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