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fiasKO [112]
4 years ago
14

A newspaper carrier has $3.65 in change he has four more quarters then dimes but two times as many nickels as quarters how many

coins of each type does he have
Mathematics
1 answer:
77julia77 [94]4 years ago
4 0

Answer:

The number of quarter coins is 9, the number of dime coins is 5 and the number of nickel coins is 18

Step-by-step explanation:

Let

x ----> the number of quarter coins

y ---> the number of dime coins

z ---> the number of nickel coins

Remember that

1\ quarter=\$0.25

1\ dime=\$0.10

1\ nickel=\$0.05

we know that

0.25x+0.10y+0.05z=3.65 ----> equation A

x=y+4

y=x-4 ----> equation B

z=2x ----> equation C

Solve the system by substitution

substitute equation B and equation C in equation A

0.25x+0.10(x-4)+0.05(2x)=3.65

solve for x

0.25x+0.10x-0.40+0.10x=3.65

0.45x=3.65+0.40

0.45x=4.05\\x=9

<em>Find the value of y</em>

y=x-4

substitute the value of x

y=9-4=5

Find the value of z

z=2x

z=2(9)=18

therefore

The number of quarter coins is 9, the number of dime coins is 5 and the number of nickel coins is 18

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1.

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