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lions [1.4K]
3 years ago
9

The equal sides of an isosceles triangle are 2 cm shorter than the length of the third side. If the perimeter of the triangle is

35 cm, find the length of the third side.​
with the formula plsssss
Mathematics
1 answer:
Phoenix [80]3 years ago
3 0
<h3><u>Given</u><u> </u><u>Inform</u><u>ation</u><u> :</u></h3>

• Equal sides of an isosceles triangle = 2cm shorter than the length of the third side.

<h3><u>To calculate :</u></h3>

• Length of the third side.

<h3><u>Calculation :</u></h3>

Let the third side be c.

Also, two equal sides be a and b.

<u>According to the question</u>,

\longmapsto a = ( Third side - 2 ) cm

\longmapsto a = ( c - 2 ) cm

Similarly, length of b(second side) will also be same as a and b are two equal sides of an isosceles triangle.

\longmapsto b = ( c - 2 ) cm

Now, we know that :

★ Perimeter of ∆ = Sum of all sides

  • Perimeter = 35 cm.

\longmapsto 35 = a + b + c

\longmapsto 35 = (c - 2) + (c - 2) + c

\longmapsto 35 = c - 2 + c - 2 + c

\longmapsto 35 = c + c + c - 2 - 2

\longmapsto 35 = 3c - 4

\longmapsto 35 + 4 = 3c

\longmapsto 39 = 3c

\longmapsto \sf \dfrac{39}{3} = c

\longmapsto 13 = c

So, third side of the triangle is <u>13 cm</u>.

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Method 1: Rewrite as product of
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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


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