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Andrew [12]
3 years ago
6

If 40% is equal to the fraction X over 30 what is the value of X

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer: the answer is 12

Step-by-step explanation:

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The industrial process that is used to convert a fuel to gasoline is carried out at a temperature range of 660 degrees°F to 790
NARA [144]

Answer:

|F-725|

With F represent the variable of interest:

-65< F-725< 65

-65+725< F< 65+725

660 < F< 790

Step-by-step explanation:

For this case we have a normal limits for the temperature Range. The minimum is 660 F and the maximum 790 F.

We can find the midpoint of this interval like this:

Midpoint= \frac{660+790}{2}= 725

And the difference between the midpoint and the limits are:

|790-725|= 65

|680-725|= 65

So then we can create the following inequality:

|F-725|

With F represent the variable of interest.:

-65< F-725< 65

-65+725< F< 65+725

660 < F< 790

5 0
3 years ago
Which of the following expressions could be used to find the perimeter of this figure?
Burka [1]

Answer:

A

Step-by-step explanation:

four of the sides are equal to 18mm, so that would be the 4(18mm), and then the two other sides are equal to 24mm, which is 2(24mm). Your full equation would be:

P= 4(18mm) + 2(24mm)

A

4 0
3 years ago
Read 2 more answers
What is the area of this figure? 4 cm 5 cm 5 cm​
Zarrin [17]

Answer:

100

Step-by-step explanation:

5*5*4=100

5 0
2 years ago
Someone please help me with this answer please it’s times and I need help real answers please
NemiM [27]
249-76=173. Answer is a
5 0
2 years ago
An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t
alina1380 [7]

Answer:

Step-by-step explanation:

Given

Height of building is h=110\ ft

Initial upward velocity u=23\ ft/s

height of object is given by

z(t)=ut+\frac{1}{2}gt^2

but building is already at a height of 110 ft so z(t) must be given by

Z(t)=ut+\frac{1}{2}(-g)t^2+110

Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2

Z(t)=-16t^2+23t+110

Time when it hits is given by when Z(t)=0[/tex]

-16t^2+23t+110=0

t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}

t=\frac{-23\pm 87}{-32}

t=3.43\ s

6 0
3 years ago
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