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alina1380 [7]
3 years ago
6

I need some help ? Does anyone know this:)I’m new too this thats why im asking loll

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer: Its the second choice

Step-by-step explanation: square area is base x height; the base is 12 the height is 4. triangle area = (base x height)/ 2; base is 12, times 4 (height), then divide by 2

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the length of a rectangle is 5 inches more then the width. the area of the rectangle is equal to 2 inches more than 4 times the
Svet_ta [14]
P = 2(L + W)
L = W + 5
A = 4P + 2

P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10

A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42

A = L * W
A = W(W + 5)
A = W^2 + 5W

W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0

W - 14 = 0
W = 14 <==

L = W + 5
L = 14 + 5
L = 19 <==

P = 2(19 + 14)
P = 2(33)
P = 66

A = L * W
A = 19 * 14
A = 266

answer : length = 19, width = 14....perimeter = 66....area = 266
5 0
3 years ago
A hair salon completed a survey of 367 customers about satisfaction with service(Dissatisfied, Neutral, Satisfied, or Very Satis
mamaluj [8]

The results of the survey are shown in the table.

It's required to calculate the following probabilities:

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The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.

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p=\frac{79}{367}

b) A customer is a walk-in

The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is

p=\frac{106}{367}

c) A customer is dissatisfied and a walk-in.

We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.

The required probability is:

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d) A customer is very satisfied given he saw a TV ad.

This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:

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Total satisfied = 139

Total referred = 150

With both features = 62

Total customers with one or both features: 139 + 150 - 62 = 227

We have to subtract the common feature because it was counted twice.

The required probability is:

p=\frac{227}{367}

6 0
1 year ago
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Lilit [14]

Answer:

160D^2

Step-by-step explanation:

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yulyashka [42]

Answer:

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