Tried a couple times but cant seem to find the answer, would appreciate an explanation.
1 answer:
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Answer:
The given line segment whose end points are A(2,2) and B(3,8).
Distance AB is given by distance formula , which is
if we have to find distance between two points (a,b) and (p,q) is
=
AB= = 6.08 (approx)
Line segment AB is dilated by a factor of 3.5 to get New line segment CD.
Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)
Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)
CD = AB × 3.5
CD = √37× 3.5
= 6.08 × 3.5
= 21.28 unit(approx)
2. Slope of line joining two points (p,q) and (a,b) is given by
m=
m=
As the two lines are coincident , so their slopes are equal.
Slope of line AB=Slope of line CD = 6
Answer:
(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.
(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).
Step-by-step explanation:
Let <em>X</em> = number of students who read above the eighth grade level.
(a)
A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.
Compute the proportion of students who can read above the eighth grade level as follows:
The proportion of students who can read above the eighth grade level is 0.8327.
Compute the proportion of tenth graders reading at or below the eighth grade level as follows:
Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.
(b)
the information provided is:
<em>n</em> = 709
<em>X</em> = 546
Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:
The critical value of <em>z</em> for 95% confidence interval is:
Compute the 95% confidence interval for the population proportion as follows:
Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).