Answer:
(b)0.56
(c)0.38
Step-by-step explanation:
(a)
P(Ben Pass) =0.8
Therefore: P(Ben fails)=1-0.8 =0.2
P(Tom Pass) =0.7
Therefore: P(Tom fails)=1-0.7 =0.3
See attached for the completed tree diagram
(b)Probability that both will pass
P(both will pass)=P(Ben pass and Tom pass)
=P(Ben pass) X P(Tom pass)
=0.8 X 0.7
=0.56
(c)The probability that only one of them will pass
Since either Tom or Ben can pass, we have:
P(only one of them will pass)
=P(Ben pass and Tom fails OR Ben Fails and Tom Pass)
=P(Ben pass and Tom fails)+P(Ben Fails and Tom Pass)
=(0.8 X 0.3) + (0.2 X 0.7)
=0.24 + 0.14
=0.38
Add All The Numbers (Which Gives You 19.43) Then Divide By Four Because There Are Four Numbers That Were Added Together. The Average Is 4.8575.
Step-by-step explanation:
x1=2. y1=1. x2=4. y2=5
by midpoint formula,
2+ 4/2 = 6/2 =3
1+5 /2 =6/2 = 3
therefore,the midpoints are (3,3)
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Answer:
Find out the how much did each roll of crepe paper cost .
To prove
Let us assume that the cost of the roll of crepe paper be x.
Let us assume that the cost of the balloon be y .
As given
For party decorations, you buy 6 rolls of crepe paper and 20 balloons for $11.90.
Than the equation becomes
6x + 20y = 11.90
As given
After you start decorating, you determine that you need more party decorations.
You buy 2 more rolls of crepe paper and 15 more balloons for $6.05.
Than the equation becomes
2x + 15y = 6.05
Than two equations are
6x + 20y = 11.90 and 2x + 15y = 6.05
Multiply 2x + 15y = 6.05 by 3 and subracted with 6x + 20y = 11.90
6x - 6x + 45y -20y = 18.15 - 11.90
25y = 6.25
y = $0.25
Put in the equation 2x + 15y = 6.05
2x + 15 × 0.25 = 6.05
2x = 6.05 - 3.75
2x = 2.3
x = $1.15
Therefore the each roll of crepe paper cost is $1.15 .
5
Write -22 in the middle of the graph, number the rest of the graph accordingly and draw an open circle around the line under the -22 and draw a line along the graph to the right
7
Write 15 in the middle of the graph and number the rest of the graph accordingly, draw a colored in circle under the 15 on the graph and draw a line to the to the right
Sorry, I'm on the road and couldn't take a picture of the solution
