The 3 inside angles of a triangle need to equal 180 degrees.
Since you are given 2 angles, subtract both of those from 180 to find X.
X = 180 - 70 - 30 = 80 degrees.
X = 80
Answer:
The equation is:
f (t) = 4 + 5 (1 - cos (2pi t / 2))
Step-by-step explanation:
with the previous exercise we look for the equation for h = f (t)
So the data we have are
Wheel diameter = 10m (wheel radius = 5m)
1 wheel gets 1 revolution in 2 minutes.
the beginning of a entry will be related to that f (0) = 4
our wish is that f (z) get at least 4 with an amplitude of 5 (this value determines the radius of the wheel) for 2 minutes
with this the particle f (t) is transformed into
f (t) = 4 + 5 (1 - cos (2pi t / 2))
We know that the maximum value of cos in t will be 0, 1 -cos has minutes, the result will be as follows:
f (t) = 4 + 5 (1 - cos (2pi t / 2))
Answer:
y = -4x - 1
Step-by-step explanation:
Do the slope formula first to find the slope. Next do point slope form to find the y intercept and write the equation in slope intercept form.
Answer: 3
Step-by-step explanation: [ 3.6 ] represents the greatest integer function [ x ]
If x is an integer use that integer
If x is not an integer use the next smaller integer
[ 3.6 ] is not an integer, hence
[ 3.6 ] = 3
Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
__
The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
