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3 years ago

Consider the equations y = √x and y = x^2 - 1

Mathematics

1 answer:

lord [1]3 years ago

8 0

<h3>Answer:</h3>

(x, y) ≈ (1.49021612010, 1.22074408461)

<h3>Explanation:</h3>

This is best solved graphically or by some other machine method. The approximate solution (x=1.49, y=1.221) can be iterated by any of several approaches to refine the values to the ones given above. The values above were obtained using Newton's method iteration.

_____

Setting the y-values equal and squaring both sides of the equation gives ...

... √x = x² -1

... x = (x² -1)² = x⁴ -2x² +1 . . . . . square both sides

... x⁴ -2x² -x +1 = 0 . . . . . polynomial equation in standard form.

By Descarte's rule of signs, we know there are two positive real roots to this equation. From the graph, we know the other two roots are complex. The second positive real root is extraneous, corresponding to the negative branch of the square root function.

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Solve for r. <br><br> √2/3r + 1 = 23

Keith_Richards [23]

Answer:

2nd option

Step-by-step explanation:

$\frac{\sqrt{2} }{3}$ r + 1 = 23 ( subtract 1 from both sides )

$\frac{\sqrt{2} }{3}$ r = 22 ( multiply both sides by 3 to clear the fraction )

$\sqrt{2}$ r = 66 ( divide both sides by $\sqrt{2}$ )

r = $\frac{66}{\sqrt{2} }$ × $\frac{\sqrt{2} }{\sqrt{2} }$ ( rationalising the denominator )

r = $\frac{66\sqrt{2} }{2}$ = 33 $\sqrt{2}$

7 0

3 years ago

Read 2 more answers

Lincoln has 16 pins in one box and 17 pins in another box. He is hanging posters with the pins. Lincoln uses 4 pins to hang each

frez [133]

Answer: 8 posters

Step-by-step explanation:

From the question, we are informed that Lincoln has 16 pins in one box and 17 pins in another box and that he uses 4 pins to hang each posters posted. The total number of posters he can hang with the pins goes thus:

We should first calculate the total number of pins he has.

= 16 + 17 = 33 pins

Since he uses 4 pins to hang a poster, we then divide 33 pins by 4.

= 33 ÷ 4

= 8.25

This means that he can hang 8 posters with the pin

8 0

3 years ago

One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.

enot [183]

Answer: There will enough to paint the outside of a typical spherical water tower.

Step-by-step explanation:

1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:

$V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}$

2. Substitute values:

$r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft$

3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:

$SA=4r^{2}\pi\\SA=4(25.17ft)^{2} \pi\\SA=7,964.95ft^{2}$

3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.

$25*400ft^{2}=10,000ft^{2}$