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Nastasia [14]
3 years ago
12

How many inches are in 1 & 2/5 groups of 1 & 2/3 inches? *

Mathematics
2 answers:
Alex Ar [27]3 years ago
6 0
Then set v v to can b do CNN mr CB en beg bhbb hub. 4645 35)5
Anni [7]3 years ago
3 0
I’d start by converting to improper fractions. 7/5 and 5/3.
7/5 groups of 5/3
= 7/5 x 5/3
= 35/15
= 2 5/15
= 2 1/3 inches
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Mr. Johnson buys 5 bottles of lemonade for the school picnic. He buys four 28
Murljashka [212]

Answer:

180

Step-by-step explanation:

112+64

=112+64

=176

4 0
3 years ago
Simplify 6(4x - 3) show work plz
WITCHER [35]

Answer:

24x-18

Step-by-step explanation:

To simplify this we will need to use the distributive property

we can start with

6*4x=24x

then we can do

6*3=18

and since their is a negative sign in the middle that is what we do, so it will be

24x-18

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7 0
3 years ago
Read 2 more answers
In mostar, bosnia, the ultimate test of a young man's courage once was to jump off a 400-year-old bridge (now destroyed) into th
Alex787 [66]

To solve this problem, we must assume that the man undergoes constant acceleration as he goes down the river (therefore no other forces must act on him except gravity). Therefore we can use the formula below to calculate for the duration of his fall:

y = y0 + v0 t + 0.5 a t^2

where y is the distance and y0 = 0 since we set the reference point at the bridge, v0 is the initial velocity and is also equal to v0 = 0 since the man started from rest, therefore the equation becomes:

y = 0 + 0 t + 0.5 a t^2

y = 0.5 a t^2

Rewriting in terms of t:

t^2 = 2 y / a

t = sqrt (2y / a)

a is acceleration due to gravity = 9.8 m/s^2

t = sqrt [2 * 23 / 9.8]

t = 2.17 s

 

Therefore the jump last only about 2.17 seconds.

6 0
3 years ago
(Question 1)
Burka [1]
I got C as the answer
5 0
3 years ago
The loudness, L, of a sound (measured in decibels, dB) is inversely proportional to the square of the distance, d
Klio2033 [76]

Answer:

L = 9.91 decibels.

Step-by-step explanation:

The loudness, L is inversely proportional to the square of the distance, d, from the source of the sound.

i.e L \alpha \frac{1}{d^{2} }

L = \frac{k}{d^{2} }

Where k is the constant of proportionality.

When d = 14 feet and L = 85 dB, then;

k = L x d^{2}

  = 85 x (14)^{2}

 = 16660

k = 16660

L = \frac{16660}{d^{2} }

Thus, when d = 41 feet, then;

L = \frac{16660}{(41)^{2} }

  = \frac{16660}{1681}

  = 9.91077

L = 9.91 dB

The loudness is 9.91 decibels.

5 0
3 years ago
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