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ira [324]
2 years ago
15

A university will add fruit juice vending machines to its classroom buildings if the student body president is convinced that mo

re than 20 percent of the students will use them. A random sample of n students will be selected and asked whether or not they would use the vending machines. A large-sample test for proportions at the significance level of α = 0.05 will be performed. The null hypothesis that the proportion of all students who would use the vending machines is 20 percent will be tested against the alternative that more than 20 percent of all students would use them. For which of the following situations would the power of the test be highest?
A
The sample size is n = 750, and 20 percent of all students use the vending machines.

B
The sample size is n = 750, and 25 percent of all students use the vending machines.

C
The sample size is n = 1,000, and 25 percent of all students use the vending machines.

D
The sample size is n = 500, and 50 percent of all students use the vending machines.

E
The sample size is n = 1,000, and 50 percent of all students use the vending machines.
Mathematics
1 answer:
Artemon [7]2 years ago
5 0

Answer:

E) The sample size is n = 1,000, and 50 percent of all students use the vending machines.

Step-by-step explanation:

CollegeBoard

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7 0
3 years ago
State whether the lines are parallel, perpendicular,or neither.
cluponka [151]

Answer:

Please check the explanation.

Step-by-step explanation:

  • Two lines are parallel if their slopes are equal.
  • Two lines are perpendicular if the product of their slope is -1

We also know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept

Given the lines

1)

  • y = 6х - 3

Comparing with y=mx+b, the slope of y = 6х - 3:

m₁=6  

  • y = - 1/6x + 7

Comparing with y=mx+b, the slope of y = - 1/6x + 7:

m₂=-1/6

As

m₁ × m₂ = -1

6 ×  - 1/6 = -1

-1 = -1

Thus, the lines y = 6х - 3 and y = - 1/6x + 7 are perpendicular.

2)

  • y = 3x + 2

Comparing with y=mx+b, the slope of y = 3x + 2:

m₁=3  

  • 2y = 6x - 6

simplifying to write in slope-intercept form

y=3x-3

Comparing with y=mx+b, the slope of y=3x-3:

m₂=3

As the slopes of y = 3x + 2 and 2y = 6x - 6 are equal.

i.e. m₁ = m₂ → 3 = 3

Thus, the lines y = 3x + 2 and 2y = 6x - 6 are paralle.

3)

  • 8x - 2y = 3

simplifying to write in slope-intercept form

y = 4x - 3/2

Comparing with y=mx+b, the slope of y = 4x - 3/2:

m₁=4  

  • x + 4y = - 1

simplifying to write in slope-intercept form

y=-1/4x-1/4

Comparing with y=mx+b, the slope of y=-1/4x-1/4:

m₂=-1/4

As

m₁ × m₂ = -1

4 ×  - 1/4 = -1

-1 = -1

Thus, the lines 8x - 2y = 3 and x + 4y = - 1 are perpendicular.

4)

  • 3x+2y = 5

simplifying to write in slope-intercept form

y = -3/2x + 5/2

Comparing with y=mx+b, the slope of y = -3/2x + 5/2:

m₁=-3/2  

  • 3y + 2x = - 3

simplifying to write in slope-intercept form

y = -2/3x - 1

Comparing with y=mx+b, the slope of y = -2/3x - 1:

m₂=-2/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

5)

  • y - 5 = 6x

simplifying to write in slope-intercept form

y=6x+5

Comparing with y=mx+b, the slope of y=6x+5:

m₁=6  

  • y - 6x = - 1

simplifying to write in slope-intercept form

y=6x-1

Comparing with y=mx+b, the slope of y=6x-1:

m₂=6

As the slopes of y - 5 = 6x and y - 6x = -1 are equal.

i.e. m₁ = m₂ → 6 = 6

Thus, the lines y - 5 = 6x and y - 6x = -1 are paralle.

6)

  • y = 3х + 9

Comparing with y=mx+b, the slope of y = 3х + 9:

m₁=3  

  • y = -1/3x - 4

Comparing with y=mx+b, the slope of y =  1/3x - 4:

m₂=1/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

8 0
2 years ago
Im really bad in math so could anyone help me please
emmasim [6.3K]
Answer is
5, the third option
7 0
2 years ago
Read 2 more answers
Show work / explain it ​
aivan3 [116]
Answer:
X 1 = -4,X 2 =12

EXPLANATION:

Determine the defined range
X+6/x=6/x-8,x#0,x#8

Simplify the equation using cross-multiplication
(X+6) x (x-8)=6x

Move variable to the left-hand side and change its sign
(X-6)x(x-8)-6x=0

Multiply the parentheses
X^2-8x+6x-48-6x=0

Since two opposites add up to zero, remove them from the expression
X^2-8x-48=0

Write -8x as a difference
X^2+4x-12x-48=0

Factor out x from the expression
Xx(x+4)-12x-48=0

Factor out -12 from the expression
Xx(x+4)-12(x+4)=0

Factor out from the expression
(x+4)x(x-12)=0

When the product of factors equals 0, at least one factor is 0
x+4=0
x-12=0

Solve the equation for x
X=-4
X-12=0
X=-4,x#0,x#8

Check if the solution is in the defined range
X=-4
x=12

The equation has 2 solutions

X 1 = -4,X 2 =12

Hope this helps


3 0
3 years ago
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