Which equation could represent the relationship shown in the

Test the ability of auto mechanics to identify simple engine problems, an automobile with a single suchproblem was taken to 72 d

jekas [21]

Answer:

The proportion is less than 0.75 only

Step-by-step explanation:

given that the ability of auto mechanics to identify simple engine problems, an automobile with a single suchproblem was taken to 72 different car repair facilities.

Sample proportion $= 42/72=0.5833$

Set up hypotheses as

H0: p =0.75

Ha: p < 0.75

(Left tailed test)

Assuming H0 to be true, std error of proportion = $\sqrt{\frac{0.75*0.25}{72} } \\=0.0668$

p difference = -0.1667

Test statistic Z = p diff/std error = -2.50

p value = 0.0062

since p is less than0.05 at 5% significance level we reject null hypothesis

The proportion is less than 0.75 only

6 0

3 years ago

Exclude leap years from the following calculations. (a) Compute the probability that a randomly selected person does not have a

Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0

3 years ago

Divide.<br><br> 36/4,104<br><br> Enter your answer in the box.

Gnom [1K]

Answer:

114

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which of the following rational exponent expressions is NOT simplified correctly as a radical expression?

mrs_skeptik [129]

Answer:

4th one

Step-by-step explanation:

$x^{\frac{5}{6} }$ must be $\sqrt[6]{x^{5} }$

8 0

3 years ago

Hi! I need help with this problem: 5^2-(2x7^2)

Ahat [919]

5^2=25
25-(2x7^2)
7^2=49
25-(2x49)
49x2=98
25-98=-73
Answer= -73

7 0

3 years ago