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Yanka [14]
3 years ago
15

Which one is greater 1/75 or 1/3

Mathematics
2 answers:
umka21 [38]3 years ago
6 0

Step-by-step explanation:

\frac{1}{75}  \\  \frac{1}{3}  =  \frac{1  \times 15}{3  \times 15}  =  \frac{15}{75}

Hence, 1/3 is greater.

svetoff [14.1K]3 years ago
4 0

Answer:

1/3 is greater

Step-by-step explanation:

Mark me brainlist

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Answer:

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4 years ago
Get brainly if right?<br> 10 points!
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Answer:

Tn = -13n +37

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3 years ago
How many of the numbers from the set $\{1,\ 2,\ 3,\ldots,\ 50\}$ have a perfect square factor other than one?
Novay_Z [31]

Answer:

2^2 ( 1,2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)  =  4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44,48

3^2(1,2,3, 5)   =  9, 18, 27, 45

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Step-by-step explanation:

5 0
4 years ago
Response Question
Paha777 [63]

Answer:

The right solution is "3.29, 3.57".

Step-by-step explanation:

Seems that the given problem is incomplete. Below is the attachment of the complete and appropriate query.

<u>The given values are</u>:

Randomly selected adults,

n = 105

Mean,

\bar{x} = 3.42

Standard deviation,

s = 0.75

Now,

At 95% confidence level if given by,

=  \bar{x} \ \pm \ Z_{\frac{\alpha}{2} }\times \frac{s}{\sqrt{n} }

On putting the given values, we get

=  3.42 \ \pm \ Z_{\frac{0.05}{2} }\times \frac{0.75}{\sqrt{105} }

=  3.42 \ \pm \ 1.96\times 0.073

=  3.42 \ \pm \ 0.143

=  3.29, 3.57

3 0
3 years ago
When three squares are joined at their vertices to form a right triangle, the combined area of two smaller squares is the same a
Artist 52 [7]

Answer:

<em>b = 12 cm</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

The area of a square of side length x is

A = x^2

We have three squares, two of which have side lengths of a=5 cm and b= 13 cm.

The combined area of the smaller squares is the same as the area of the largest square. We cannot say at first sight which square is the largest, we'll assume the square of side length of 13 cm is the largest one. Thus:

5^2+b^2=13^2

Where b is the unknown side length.

The above expression corresponds to the Pythagora's Theorem formula. Solving for b:

b^2={13^2-5^2=169-25=144

b=\sqrt{144}

b = 12 cm

7 0
3 years ago
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