176
Since you didn't bother to include a diagram of the triangle, I am going to make some assumptions. You need to actually verify that the assumptions are correct and if they are, then this answer is correct. Otherwise if the assumptions are not correct, you're on your own.
Assumption.Points B and C are midpoints of line segments AE and AD. The reason for this assumption is because if points B and C didn't lie on the sides of triangle AED, you would gain no useful information about triangle AED from the lengths provided. Additionally, if those points were not midpoints, you wouldn't gain any information about the lengths of the sides of triangle AED expect that those sides were longer than the lengths of the sides specified.
Once again. VERIFY that points B and C are midpoints of line segments AE and AD.
Now for the solution:Since triangle AED is similar to triangle ABC, that means that the ratio of the lengths of the sides is constant. And since B & C are midpoints of their respective sides, the perimeter of triangle AED is twice the perimeter of triangle ABC. And the perimeter of triangle ABC is 26 + 30 + 30 = 86. So the perimeter of triangle AED is 86 * 2 = 176
Simple,
just simplify your problem....
which just leaves you
itself...now add them up....
Making your answer...
Answer:
B. 8.0 cubic inches
Step-by-step explanation:
You need to find 190% of the volume of a gumball which is a sphere.
To find 190% of a quantity, multiply the quantity by 1.9.
volume of sphere = (4/3)(pi)(r^3)
diameter = d = 2 in.
radius = r = (1/2)d = (1/2)(2 in.) = 1 in.
volume of sphere = (4/3)(3.14159)(1 in.)^3 = 4.189 in.^3
The volume of a gumball is 4.189 in.^3
Now we need 190% of that volume.
190% of volume of sphere = 1.9 * volume = 1.9 * 4.189 in.^3 = 7.959 in.^3
Rounded to the nearest tenth, the volume is
B. 8.0 cubic inches
