if ∡PQR = 82°, and the ray QS bisects it, it cuts ∡PQR into two equal halves, ∡PQS and ∡RQS, each of which is then 82/2, or 41°.
Thirty-nine and six hundredths
The answer is the last one.
Answer:
{6,8}
Step-by-step explanation:
{5,6,7,8} intersection {6,8,9}
={6,8}
A
<span>2) right bottom [tangents drawn to a circle from the same point are equal in length] </span>
<span>3) a </span>
<span>4) b </span>
<span>[Triangles AEC and DEB are similar triangles. So corresponding sides are proportional. So, AE/DE = CE/BE.] </span>
<span>5) c </span>
<span>6) a </span>
<span>7) c </span>
<span>8) b </span>
<span>9) a </span>
<span>10) c </span>
<span>11) d </span>
<span>12) a </span>
<span>13) d </span>
<span>14) a </span>
<span>15) b </span>
<span>16) c </span>
<span>17) c </span>
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