The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m
<h3>How to find the dimensions of the rectangle?</h3>
For a rectangle of length L and width W, the diagonal is:
Here we know that the diagonal is 169m.
And the ratio of the length to the width is 12:5
This means that:
W = (5/12)*L
Replacing all that in the diagonal equation:
So the length is 156 meters, and the width is:
W = (5/12)*156 m = 65m
Finally, the perimeter is:
P = 2*(L + W) = 2*(156 m + 65m) = 442m
If you want to learn more about rectangles:
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Answer:
51,51 and 78
Step-by-step explanation:
3x+9=4x-5
3x=4x-14
-x=-14
x=14
X^2 + 2xy + -x + y^2 + -y + -12
Answer: 122.5
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Explanation:
First thing to do is to find the perimeter of figure B. Add up all the sides and we get: 5+9+9+12 = 14+21 = 35.
The scale factor 7:2 means that if the perimeter of figure A was 7, then the perimeter of figure B would be 2. Or it could be 14 for A and 4 for B. And so on. The idea is that the two perimeters scale up or down together. This allows us to set up the proportion below in which we can solve for x
(perimeter of A)/(perimeter of B) = 7/2
x/35 = 7/2
x*2 = 35*7 .... cross multiply
2x = 245
2x/2 = 245/2 .... divide both sides by 2
x = 122.5
The perimeter of figure A is 122.5
Answer:
You can either factor or use quadratic formula to find where h(x)=0
Step-by-step explanation:
Remember that the ball is on the ground when h(x)=0 since that is the height. There will be two zeros, one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.
