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3 years ago

HELP PLEASE!!!! solve for x

Mathematics

1 answer:

LenKa [72]3 years ago

7 0

Answer: how do you solve for this

Step-by-step explanation:

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Please help me with my homework.

Blababa [14]

Answer:

-3x + 6

Step-by-step explanation:

-3(x - 2) to find the equivalent of this expression, we need to multiply inside the parenthesis with -3 (with both x and -2)

-3(x - 2 = -3x + 6 (two negative expressions multiplied results in positive)

3 0

3 years ago

Write 27/22 as a decimal rounded to the nearest tenth?

Verizon [17]

Answer:

1.2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which of the following relations represent a function?

ziro4ka [17]

The answer would be c because if you see closely the function is -1 and 4 March determining the perspectives and how the procedure goes

7 0

3 years ago

Solve for n: 21 K - 3n + 9 p is greater than 3 p + 12

Digiron [165]

Answer:

n > p + 1 + 7k

Step-by-step explanation:

21k - 3n + 9 > 3p + 12

21k - 3n > 3p + 12 - 9

3n > 3p + 3

3n > 3p + 3 + 21k

n > (3p + 3 + 21k)/3

n > p + 1 + 7k

6 0

3 years ago

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago