Answer:
73, 74, 75
Step-by-step explanation:
So the sum of three consecutive integers is 222.
Let's let the first integer be n.
Then the second integer <em>must</em> be (n+1).
And the third integer must be (n+2).
They total 222, thus:

Combine like terms:

Subtract 3 from both sides:

Divide both sides by 3:

So, the first integer is 73.
So our sequence is 73, 74, and 75.
And we're done!
MOE = +\- 1.27
The 99% confidence interval ranges from 53.73 to 56.27 hours.
1) from smaller to higher:
1,5,11,11,17
2) find the mean
<span>1 + 5 + 11 + 11 + 17 = </span><span>45
</span>mean = 45/5 = 9
Variance = Σ(x- mean)²/(N-1)
[(1-9)² + (5-9)²+(11-9)² + (11-9)²+ (17-9)² ]'(5-1) = 38
Variance = 38