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kogti [31]
3 years ago
5

y<1/4x+1 y≥ 3x+2 identify one point that is a solution and identify any point that is NOT a solution

Mathematics
1 answer:
Bess [88]3 years ago
5 0

Answer:

(-1,-1) works (5,5) does not

Step-by-step explanation:

y<1/4x+1\geq3x+2

-1<1/4(-1)+1\geq3(-1)+2

-1<-1/4+1\geq-3+2

-1<.75\geq-1

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James wants to send two gifts by mail. One package weighs 2 3/4 pounds. The other package weighs 1 3/4. Want is the total weight
LUCKY_DIMON [66]
= 4 1/2 (2 3/4 + 1 3/4)

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3 years ago
(Please Help) Drag a statement or reason to each box to complete this proof.
SOVA2 [1]

Answer:

see the explanation and the attached figure

Step-by-step explanation:

we have

-2(x+1)=8 ----> given

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Simplifying

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6 0
3 years ago
How do I find an exactions for a graph
butalik [34]
3x-6 this is the answer because it rose 3 and the Y intercept is -6
8 0
3 years ago
Work out these questions without a calculator and showing all working out
natima [27]
1) 6÷0.2 = 30

If 6/2=3 then 6/0.2=30 as the decimal place shifts one place.

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8/1=8 so shift the decimal place over once to make 80.

3)9÷0.3 = 30

9/3=3 so shift the decimal place over once to get 30.

4)4÷0.04 = 100

4/4=1 so shift the decimal place over twice to get 100.

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7/2=3.5 so shift the decimal place over three times to get 3500

6)0.718÷0.2 = 3.59

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7)0.0141÷0.003 = 4.7

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Hope this helps :)
3 0
3 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
3 years ago
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