Answer:
6/5
Step-by-step explanation:
8/15 - (-2/3)
8/15 + 2/3
24 + 30/45
54/45 = 6/5
Thus, the difference between 8/15 and -2/3 is 6/5
The inequality is: 5>x≥0
Step-by-step explanation:
We have to write the inequality one by one
The inequality symbols are used to write inequalities.
So,
5 is greater than x will be written as:
5>x
And
0 is less than or equals to x:
0≤x or x≥0
We have to combine the both inequalities so that the variable is not repeated. The inequality symbols have to be written carefully while writing the compound inequalities.
5>x≥0
Keywords: Inequality, Relationships
Learn more about inequality at:
#LearnwithBrainly
Answer:
They averaged 79 km per hour
Step-by-step explanation:
To find the average distance, take the kilometers and divide by the hours
1106 km/ 14 hours
79 km / hours
They averaged 79 km per hour
Answer:
The answer is D
Step-by-step explanation:
The absolute value number is its relationship to other numbers without regards for its sign. So say the question is asked: whats the absolute value of -1. The absolute value would be positive four because 1 is one place away from 0 on the number line.
Answer:
The number of ways those textbooks could be distributed among the students is expressed by a combinations of 8(books) to 5(students), which is ![C_{8,5} = \frac{8!}{5!(8-5)!} = 56](https://tex.z-dn.net/?f=C_%7B8%2C5%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%21%288-5%29%21%7D%20%3D%2056)
Step-by-step explanation:
The order in which the students get the textbooks is not important. For example, A,B,C,D and E getting the textbooks is the same outcome as B,A,C,D and E. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
In this problem
5 textbooks to 8 students. So
![C_{8,5} = \frac{8!}{5!(8-5)!} = 56](https://tex.z-dn.net/?f=C_%7B8%2C5%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%21%288-5%29%21%7D%20%3D%2056)
The number of ways those textbooks could be distributed among the students is expressed by a combinations of 8(books) to 5(students), which is ![C_{8,5} = \frac{8!}{5!(8-5)!} = 56](https://tex.z-dn.net/?f=C_%7B8%2C5%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%21%288-5%29%21%7D%20%3D%2056)