Step-by-step explanation:
Given the following systems of linear equations, 2x + y = 5, and 3y = 9 − 6x
<h2>Write each equation in slope-intercept form. </h2>
The slope-intercept form is: y = mx + b, where m = slope, and b = y-intercept.
<h3><u>2x + y = 5</u></h3>
Subtract 2x from both sides:
2x - 2x + y = - 2x + 5
y = -2x + 5 ⇒ This is the <u>slope-intercept form</u>, where the <u>slope</u>, <em>m</em> = -2, and the <u>y-intercept</u>, <em>b</em> = 5.
<h3><u /></h3><h3><u>3y = 9 − 6x </u></h3>
Divide both sides by 3 to isolate y:
3y = − 6x + 3
y = -2x + 3 ⇒ This is the <u>slope-intercept form</u>, where the <u>slope</u>, <em>m</em> = -2, and the <u>y-intercept</u>, <em>b</em> = 3.
<h2 /><h2>What do the equations have in common? </h2>
y = -2x + 5
y = -2x + 3
These equations have the same <u>slope</u>, m = -2.
<h2>How are they different?</h2>
They have different y-intercepts.
y = -2x + 5 ⇒ The <u>y-intercept</u> is (0, 5), where <em>b</em> = 5.
y = -2x + 3 ⇒ The <u>y-intercept</u> is (0, 3), where <em>b</em> = 3.