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Savatey [412]
2 years ago
6

PLEASE HELP I WILL MAKE YOUR ANSWER THE BRAINLIEST perimeter of the parallelogram

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
6 0

Answer:

i believe its 30 but thats honestly my best guess

marysya [2.9K]2 years ago
5 0

Answer: i think the awnser is 48

Step-by-step explanation:

8+8=16 16+16+16=48

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Jackie won tickets playing the bowling game at the local arcade. The first time, she won 6 tickets. The second time, she won a b
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it might be 48 tickets.

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Calculate the distance between the points (-6, 4) and (5, -1). Round to the nearest tenth.
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It will be 42 because of the with times the 2nd highest
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12, 17, 22, ...<br> Find the 36th term.
pychu [463]

Answer:

187

Step-by-step explanation:

a=12,d=17-12=5

nth term =a+(n-1)d

36th term=12+(36-1)5

=12+(35×5)

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2 years ago
The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
Aleksandr-060686 [28]

Answer:

a)  The probability that a student has either a Visa card or a MasterCard is 0.71.  

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b)  In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards  is P(V \cap M)=0.03

a) Probability that a student has either a Visa card or a Master Card is given by,

P(V \cup M) = P(V) + P(M) - P(V\cap M)

P(V \cup M) = 0.63+ 0.11- 0.03

P(V \cup M) =0.74- 0.03

P(V \cup M) =0.71

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if P(A\cap B)=P(A)P(B)

For V and M to be independent the condition is satisfied,

P(V\cap M)=P(V)P(M)

Substitute the values,

0.03=0.63\times 0.11

0.03\neq 0.0693

So, V and M are not independent.

6 0
3 years ago
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