Answer: If you slide a hockey puck on ice, eventually it will stop, because of friction on the ice. It will also stop if it hits something, like a player's stick or a goalpost.
Explanation:
Answer:
The paintball ball launcher
Explanation:
The average speed of a paintball ball(vo) is approximately 90m/sec
and if the average speed of a ball pitcher in baseball (v1) is 150km/h
, which is equivalent to (150km/h*1000m/km*h/3600sec) = 41.66m/sec therefore the flight time of each mobile must be found to determine which one falls to the ground first
finally you can see that the shortest flight time is from the paintball ball launcher, therefore it will fall to the ground first
Note: Since the launch conditions must be the same for both, except the speed, it is placed 15º as an average value, but it can be any angle as long as it is the same for both
236.588 mL :) 1 oz=29.5735 mL
When it says something like 'on the verge of moving,' it means that the pulling force and static friction force and gravitational force all cancel out! Any more pulling force and it is ready to move!
At some point, you want F as a function of <span>μs</span>, to determine the force needed depending on the coefficient of static friction. This function, <span>F(<span>μs</span>)</span>, will rely on the angle θ as well, but we want to consider just one angle θ in every scenario. One value means it is constant.
But if we know the F, and we know <span>μs</span>, we can find what the constant angle θ must be!
If F is the pulling force, <span>FS</span> is the static friction force, and <span>FG</span> is gravitational force,
<span><span><span>Fnet</span>=0</span><span>=F+<span>FS</span>+<span>FG</span></span><span>=F+<span>FN</span><span>μs</span>+mgsinθ</span><span>=F+mgcosθ<span>μs</span>+mgsinθ</span><span>=0</span></span>
Then you can find <span>F(<span>μs</span>)</span>, but then there is the issue of solving for the θ<span> to make it true.</span>
Answer: C, supplements and drugs both undergo stringent government testing.
Explanation: took the unit test.
hope this helps :)