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ValentinkaMS [17]
2 years ago
14

sabendo que uma onda sonora tem um periodo de 0,002s e um comprimento de onda de 0,5m determine sua velocidade nesse meio

Physics
1 answer:
Artemon [7]2 years ago
3 0

Answer: Sorry i need more Details. I want to help but I dont speak spanish.

Explanation: Maybe come back later with a english question. So sorry. I hope ypu have a good Day.

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When a hammer thrower releases her ball, she is aiming to maximize the distance from the starting ring. Assume she releases the
Taya2010 [7]

Answer:

The angular velocity is 15.37 rad/s

Solution:

As per the question:

\theta = 54.6^{\circ}

Horizontal distance, x = 30.1 m

Distance of the ball from the rotation axis is its radius, R = 1.15 m

Now,

To calculate the angular velocity:

Linear velocity, v = \sqrt{\frac{gx}{sin2\theta}}

v = \sqrt{\frac{9.8\times 30.1}{sin2\times 54.6}}

v = \sqrt{\frac{9.8\times 30.1}{sin2\times 54.6}}

v = \sqrt{\frac{294.98}{sin109.2^{\circ}}} = 17.67\ m/s

Now,

The angular velocity can be calculated as:

v = \omega R

Thus

\omega = \frac{v}{R} = \frac{17.67}{1.15} = 15.37\ rad/s

8 0
3 years ago
The spring of a toy car is wound by pushing the car
Zepler [3.9K]

The elastic potential energy stored in the car's spring during the process is 3.75 J

<h3>Determination of the spring constant</h3>

From the question given above, the following data were obtained:

  • Force (F) = 15 N
  • Extention (e) = 0.5 m
  • Spring constant (K) =?

K = F/e

K = 15 / 0.5

K = 30 N/m

<h3>Determination of the potential energy</h3>
  • Spring constant (K) = 30 N/m
  • Extention (e) = 0.5 m
  • Potential energy (PE) =?

PE = ½Ke²

PE = ½ × 30 × 0.5²

PE = 15 × 0.25

PE = 3.75 J

Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J

Learn more about energy stored in spring:

brainly.com/question/4280346

7 0
2 years ago
Read 2 more answers
A simple pendulum takes 32 sec to complete 20 oscillations .what is the time period of the pendulum?
musickatia [10]
A simple pendulum that takes 32 sec. to complete 20 oscillations has a time period of 10 min. and 6 sec.
5 0
3 years ago
STOP TO THINK 17.1 Two pulses on a string approach each other at speeds of 1 m/s. What is the shape of the string at t = 6 s?
Vinvika [58]

'The principle of superposition states that when two disturbance occupy the same space at the same time the resulting disturbance is the sum of two disturbances.'

Explanation:

if two pulses are moving towards each other in the same medium and are not disturb by any external force they will approach each other and the point which will be the the sum of their individual displacement or more precisely the point of superposition of both pulses either constructive or destructive depending on the conditions given

8 0
3 years ago
A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi
docker41 [41]
<span>32 mph
   First, let's calculate the location of the particle at t=1, and t=4
 t=1
 s = 6*t^2 + 2*t
 s = 6*1^2 + 2*1
 s = 6 + 2
 s = 8 t = 4
 s = 6*t^2 + 2*t s = 6*4^2 + 2*4
 s = 6*16 + 8
 s = 96 + 8
 s = 104
   So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
 avg_vel = (104-8)/(4-1) = 96/3 = 32
   And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
6 0
3 years ago
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