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pishuonlain [190]
3 years ago
13

Guys plz help me answer this!!!!

Mathematics
2 answers:
IgorC [24]3 years ago
4 0
A=-4 is the answer hope this helps
Nutka1998 [239]3 years ago
3 0

Answer:

<u>a= -4</u>

Step-by-step explanation:

subtract 4a from both sides

add 15 to both sides

divide both sides by -3

(order of operations)

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If a/\2+1/a/\2=11, then a+1/a=?
Nadya [2.5K]

Answer:

\pm \sqrt{13}

Step-by-step explanation:

\bigg(a +  \frac{1}{a}  \bigg)^{2} =  {a}^{2}   +  \frac{1}{ {a}^{2} }  + 2 \times a \times  \frac{1}{a}  \\  \\ \bigg(a +  \frac{1}{a}  \bigg)^{2} = 11 + 2 \\  \\   \bigg(a +  \frac{1}{a}  \bigg)^{2} = 13 \\  \\  \bigg(a +  \frac{1}{a}  \bigg) =  \pm \sqrt{13}

5 0
3 years ago
Nathan went shopping for a new camera because of a sale. The store was offering a 40% discount. If the price on the tag was $35,
tia_tia [17]

Answer:

The price after the discount but before the tax is $21

Step-by-step explanation:

Here, we are told there is a price off of 40% on an item that costs $35.

What we want to calculate is the value of what the price would be before the tax

We proceed by finding 40% of $35

Mathematically, that would be;

40/100 * 35 = $14

The price of the item before the tax is thus;

35-14 = $21

4 0
3 years ago
Brianna is making fruit dip. The
STALIN [3.7K]
The answer is 6 servings
6 0
3 years ago
What is the perimeter of a square whose diagonal is 3 square root 2? Show all work on how you got your answer
Alika [10]

Answer:

12

Step-by-step explanation:

Given: Diagonal of square= 3\sqrt{2}

To find the perimeter of square, we need to find the length of sides of square.

∴ Using the formula of diagonal to find side of square.

Formula; Diagonal= s\sqrt{2}

Where, s is side of square.

⇒ 3\sqrt{2} = s\sqrt{2}

Dividing both side by √2

⇒s= \frac{3\sqrt{2} }{\sqrt{2} }

∴s= 3

Hence, Length of side of square is 3.

Now, finding the perimeter of square.

Formula; Perimeter= 4s

⇒Perimeter= 4\times 3

∴ Perimeter= 12

Hence, Perimeter of square is 12.

6 0
4 years ago
Identify the axis of symmetry and vertex of f(x) = –2x2 –2x–1.
Leya [2.2K]

<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal to the x-coordinate of the vertex. </span>

<span>Note that a quadratic equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>

4 0
3 years ago
Read 2 more answers
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