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UNO [17]
3 years ago
13

Rewrite the expression with rational exponents as a radical expression by extending the properties of integer exponents.

Mathematics
2 answers:
Andrew [12]3 years ago
8 0

Answer:

yes, the the fourth root of two is correct

Step-by-step explanation:

i just took the test today and got it correct

arlik [135]3 years ago
6 0

Answer:

\sqrt[4]{2}

Step-by-step explanation:

We start with the original problem:

\frac{2^{3/4}}{2^{1/2}}

So first we start by applying the quotient rule for powers, which tells you that whenever you are dividing two powers that have the same base and different power, you can copy the base and subtract the powers:

\frac{b^{a}}{b^{c}}=b^{a-c}

so:

\frac{2^{3/4}}{2^{1/2}}=2^{\frac{3}{4}-\frac{1}{2}}

which yields:

2^{\frac{1}{4}}

since we are talking about a rational exponent, we can next turn it into a radical by using the following rule:

b^{\frac{1}{a}}=\sqrt[a]{b}

so:

2^{\frac{1}{4}}=\sqrt[4]{2}

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Step-by-step explanation:

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Answer:

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I need help with question #2
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3 years ago
What’s this question
yKpoI14uk [10]
<h3>Hm ok, so the correct answer here would be (0,3) and heres why:</h3>

If the y would be equal to 0, everything would then just depend if you add or subtract the x:

y-x=-3\\\\y+x=3\\\\y= 0\\x=3\\\\then:\\\\0-3=3\\and\\0+3=3

Now the first answer could be correct for:

y-x=-3\\because\ if\\\\y=-3 \ and \ x=0 \ then\\-3-0=-3

However, this answer is not correct for the other equation. the same true for all the other answers except (0,3)

<h3>Now if you like this answer and want to see more, please punch that Like button, Comment, and Rate this answer! Also, make sure to send me a friend request. I'm always up for a challenge!</h3><h2>Thanks!</h2>

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